多列数据透视样式计算

我有一个用户团队的MySQL表，并为每个用户有一个player1，player2 & player3字段。多列数据透视样式计算

我想从所有用户跨为3球员列计算总选定的球员..

即

user1可以挑选playerA，playerC & playerG。

user2可以选择playerE，playerF & playerH。

user3可以挑选playerB，playerA & playerF。

user4可以挑选playerC，playerE & playerA。

我可以运行IE

SELECT player1, count(*) as total from users; 
SELECT player2, count(*) as total from users; 
SELECT player3, count(*) as total from users;

对每个球员列声明的问题是我需要一个包罗万象的结果集，将显示我的总的选择，所以我将有类似下面的所有球员

player  total 
playerA  3 
playerB  1 
playerC  2 
playerE  2 
playerF  2 
playerG  1 
playerH  1

我的表结构如下

CREATE TABLE `leaderboard_api` (
    `id` int(11) unsigned NOT NULL AUTO_INCREMENT, 
    `competition_id` char(3) DEFAULT NULL, 
    `year` year(4) DEFAULT NULL, 
    `position` int(4) DEFAULT NULL, 
    `name` varchar(128) DEFAULT NULL, 
    `player1_name` varchar(128) DEFAULT NULL, 
    `player1_score` tinyint(11) DEFAULT NULL, 
    `player2_name` varchar(128) DEFAULT NULL, 
    `player2_score` tinyint(11) DEFAULT NULL, 
    `player3_name` varchar(128) DEFAULT NULL, 
    `player3_score` tinyint(11) DEFAULT NULL, 
    `total_score` tinyint(11) DEFAULT NULL, 
    `missed_cut` tinyint(1) DEFAULT NULL, 
    `withdrawn` tinyint(1) DEFAULT NULL, 
    PRIMARY KEY (`id`) 
);

WHE ñ我运行以下

select player1_name, count(player1_name) as total from leaderboard_api where year = '2015' and competition_id = '014' group by player1_name order by total desc;

我得到一个球员列表和他们各自的计数。然后，我可以分别为player2_name和player3_name运行此操作，并获得它们的总计。

我遇到的问题是将每个玩家总数从每个查询添加到另一个以获得总计。我已经分别运行并获得了预期的值。

我试过@sagi下面的解决方案，但它不计算所有3个查询的总和，只给我1个总数。

SELECT t.player,count(*) FROM (
    SELECT player1 as player FROM `users` UNION ALL 
    SELECT player2 FROM `users` UNION ALL 
    SELECT player3 FROM `users` UNION ALL 
    ....) t 
GROUP BY t.player

这是前100使用查询

select id, player1_name, player2_name, player3_name from leaderboard_api limit 100;

输出：

1 Donald, Luke Toms, David Bradley, Keegan 
2 Stricker, Steve Bradley, Keegan Watson, Bubba 
3 Choi, KJ Westwood, Lee Bradley, Keegan 
4 Scott, Adam Stricker, Steve Immelman, Trevor 
5 Stricker, Steve Garcia, Sergio Haas, Bill 
6 Fowler, Rickie Schwartzel, Charl Bradley, Keegan 
7 Watney, Nick Stricker, Steve Levin, Spencer 
8 Stricker, Steve Johnson, Zach Bradley, Keegan 
9 Donald, Luke Points, DA Fowler, Rickie 
10 Westwood, Lee Donald, Luke Barnes, Ricky 
11 Schwartzel, Charl Choi, KJ Haas, Bill 
12 Woodland, Gary Choi, KJ Garcia, Sergio 
13 Donald, Luke Stricker, Steve Molder, Bryce 
14 Garcia, Sergio Kuchar, Matt Furyk, Jim 
15 Noh, Seung-Yul Kuchar, Matt Watney, Nick 
16 Donald, Luke Mickelson, Phil Barnes, Ricky 
17 Scott, Adam Fowler, Rickie Noren, Alexander 
18 Johnson, Zach Molinari, Francesco Toms, David 
19 Choi, KJ Westwood, Lee Poulter, Ian 
20 Mcilroy, Rory Points, DA Westwood, Lee 
21 McIlroy, Rory Donald, Luke Na, Kevin 
22 Choi, KJ Scott, Adam Dyson, Simon 
23 Fowler, Rickie Johnson, Zach Bradley, Keegan 
24 Mcilroy, Rory Scott, Adam Senden, John 
25 Mickelson, Phil Kuchar, Matt Barnes, Ricky 
26 Jimenez, Miguel Angel Mickelson, Phil Westwood, Lee 
27 Donald, Luke Mcilroy, Rory Palmer, Ryan 
28 Mickelson, Phil Choi, KJ Poulter, Ian 
29 Mcilroy, Rory Mickelson, Phil Points, DA 
30 Johnson, Zach Stricker, Steve Molinari, Francesco 
31 Toms, David Love, Davis Mickelson, Phil 
32 McIlroy, Rory Westwood, Lee Wilson, Mark 
33 Mcilroy, Rory Garcia, Sergio Immelman, Trevor 
34 Garcia, Sergio Love, Davis Westwood, Lee 
35 Donald, Luke Stricker, Steve Sabbatini, Rory 
36 Mcilroy, Rory Karlsson, Robert Romero, Andres 
37 Choi, KJ Yang, Y.E Toms, David 
38 Mcilroy, Rory Watney, Nick Kirk, Chris 
39 Mcilroy, Rory Kuchar, Matt Noren, Alexander 
40 Scott, Adam Yang, Y.E Romero, Andres 
41 Donald, Luke Fowler, Rickie Jimenez, Miguel Angel 
42 Donald, Luke Jimenez, Miguel Angel Fowler, Rickie 
43 Donald, Luke Love, Davis Choi, KJ 
44 Mcilroy, Rory Westwood, Lee Barnes, Ricky 
45 Donald, Luke Fowler, Rickie Molinari, Edoardo 
46 Garcia, Sergio Choi, KJ Yang, Y.E 
47 Choi, KJ Fowler, Rickie Dyson, Simon 
48 Fowler, Rickie Molinari, Francesco Johnson, Zach 
49 Stricker, Steve Choi, KJ Casey, Paul 
50 McIlroy, Rory Choi, KJ Molinari, Francesco 
51 Fowler, Rickie Jimenez, Miguel Angel Mickelson, Phil 
52 Mcilroy, Rory Garcia, Sergio Kim, Kyung-Tae 
53 Mcilroy, Rory Garcia, Sergio Kim, Kyung-Tae 
54 Mcilroy, Rory Mickelson, Phil Barnes, Ricky 
55 Mcilroy, Rory Mickelson, Phil Barnes, Ricky 
56 Fowler, Rickie Mcilroy, Rory Wilson, Mark 
57 Fowler, Rickie Love, Davis Watson, Bubba 
58 Fowler, Rickie Harrington, Padraig Poulter, Ian 
59 McIlroy, Rory Mickelson, Phil Jimenez, Miguel Angel 
60 Mcilroy, Rory Fowler, Rickie Jimenez, Miguel Angel 
61 Day, Jason Johnson, Zach Bradley, Keegan 
62 Stricker, Steve Overton, Jeff Mickelson, Phil 
63 Day, Jason Furyk, Jim Toms, David 
64 Donald, Luke Westwood, Lee Gay, Brian 
65 Stricker, Steve Day, Jason Kim, Kyung-Tae 
66 Mahan, Hunter Stricker, Steve Van Pelt, Bo 
67 Day, Jason Scott, Adam Barnes, Ricky 
68 Day, Jason Johnson, Zach Love, Davis 
69 Fowler, Rickie Jacobson, Fredrik Bradley, Keegan 
70 Karlsson, Robert Watney, Nick Quiros, Alvaro 
71 Schwartzel, Charl Johnson, Dustin Love, Davis 
72 Mcilroy, Rory Scott, Adam Slocum, Heath 
73 Day, Jason Johnson, Zach Dyson, Simon 
74 Day, Jason Johnson, Zach Dyson, Simon 
75 Day, Jason Mcilroy, Rory Garrigus, Robert 
76 Donald, Luke Mcilroy, Rory Byrd, Jonathan 
77 Baddeley, Aaron Garcia, Sergio Toms, David 
78 Day, Jason Kuchar, Matt Sabbatini, Rory 
79 Johnson, Dustin Choi, KJ Fisher, Ross 
80 Simpson, Webb Stricker, Steve Yang, Y.E 
81 Day, Jason Mickelson, Phil Barnes, Ricky 
82 Johnson, Zach Howell, Charles Snedeker, Brandt 
83 Donald, Luke Mcilroy, Rory Stallings, Scott 
84 Kim, Anthony Mickelson, Phil Rose, Justin 
85 Kaymer, Martin Marino, Steve Westwood, Lee 
86 Mahan, Hunter Kaymer, Martin Poulter, Ian 
87 Mcilroy, Rory Johnson, Dustin Jimenez, Miguel Angel 
88 Mcilroy, Rory Johnson, Dustin Jimenez, Miguel Angel 
89 Laird, Martin Scott, Adam Snedeker, Brandt 
90 Johnson, Dustin Johnson, Zach Manassero, Matteo 
91 Day, Jason Watney, Nick Tringale, Cameron 
92 Garcia, Sergio Day, Jason Quiros, Alvaro 
93 Day, Jason Moore, Ryan Toms, David 
94 Day, Jason Mcilroy, Rory Barnes, Ricky 
95 Baddeley, Aaron Mcilroy, Rory Yang, Y.E 
96 Westwood, Lee Jacobson, Fredrik Kim, Kyung-Tae 
97 Day, Jason Mcilroy, Rory Molinari, Edoardo 
98 Day, Jason Garcia, Sergio Cink, Stewart 
99 Bjorn, Thomas Scott, Adam Woods, Tiger 
100 Day, Jason Johnson, Dustin Levin, Spencer

来源

2016-04-03 Alan

你能告诉我们你的原始表，或至少从它的样本？ –

你应该有一个连接表，每个使用者和每个玩家一行。。。可能被称为'UserPlayers'。 –

添加了上面的创建表代码（如果有帮助的话） – Alan

从@sagi上面解决方案开始，我最终解决了这个问题，如果这是正确的语言，那么子表中的计数就会丢失。

这是我为那些可能需要它的解决方案...

select t.player, sum(count) as total from (
select player1_name as player, count(player1_name) as count from leaderboard_api where year = '2015' and competition_id = '033' group by player1_name 
UNION 
select player2_name, count(player2_name) as count from leaderboard_api where year = '2015' and competition_id = '033' group by player2_name 
UNION 
select player3_name, count(player3_name) as count from leaderboard_api where year = '2015' and competition_id = '033' group by player3_name) 
t group by t.player order by total desc

来源

2016-04-07 20:11:20 Alan

如果我理解正确的话，你可以使用UNION ALL：

SELECT t.player,count(*) FROM (
    SELECT player1 as player FROM `users` UNION ALL 
    SELECT player2 FROM `users` UNION ALL 
    SELECT player3 FROM `users` UNION ALL 
    ....) t 
GROUP BY t.player

编辑：我认为你的n有空位埃姆斯所以他们不分组为一组，试试这个：

SELECT replace(t.player,' ',''),count(*) FROM (
    SELECT player1 as player FROM `users` UNION ALL 
    SELECT player2 FROM `users` UNION ALL 
    SELECT player3 FROM `users` UNION ALL 
    ....) t 
GROUP BY replace(t.player,' ','')

您也可以尝试更换该行：

replace(t.player,' ','')

随着该行：

trim(t.player)

取决于如何恰好你的数据看起来像。

来源

2016-04-03 14:10:05 sagi

这就是我正在寻找的，但问题是count是全部1，我正在寻找t.player在所有3列中的总共出现次数。所以如果“player A”出现在player1中3次，player2出现5次而player3出现4次，那么上面的结果集应该将“player A”的次数定义为12，如果有意义的话？ – Alan

我给你的查询有什么问题？这就是它所做的。 @alan – sagi

它只是使用count（*）将所有行总计为1，我正在寻找t.player每次出现的实际次数，因此如果playerA在player1中出现3次，在player2中出现4次，在player5中出现5次player3，那么我应该得到t.player = playerA和total = 12。这是否让它变得清晰？ – Alan

多列数据透视样式计算

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