做一个三代表在MySQL

Question

加盟这是我的表

program_join ('program_join_id, member_ID, program_schedule_id'); 

program_schedule (program_scedule_id, program_id, datetime'); 

program ('program_id, program_name); 

这是我的MySQL

$mySql = "SELECT 
      program_join.program_join_id, 
      member.member_username, 
      program_join.program_schedule_id 

      FROM program_join 

       INNER JOIN member ON 
       program_join.member_ID=member.member_ID 
       ORDER BY program_join_id"; 


$myQry = mysql_query($mySql, $DB) or die ("wrong query : ".mysql_error()); 
$number = $hal; 
while ($myData = mysql_fetch_row($myQry)) { 
    $number++; 
    $code = $myData[0]; 
?> 
<tr align="center"> 
    <td><?php echo $number;?></td> 
    <td><?php echo $myData[1];?></td> 
    <td><?php echo $myData[2];?></td> 

结果

No  username  program schedule 
1  lalala   1 
2  bababba   2 

下的 '节目表'，我想从'program_join.program_schedule_id'显示节目名称

请帮我

Answer 1

只需使用连接从节目表中获取program_name即可：

SELECT 
pj.program_join_id, 
m.member_username, 
p.program_name, 
ps.datetime 

FROM program_join pj 
INNER JOIN member m ON pj.member_ID=m.member_ID 
INNER JOIN program_schedule ps ON ps.program_schedule_id = pj.program_schedule_id 
INNER JOIN program p ON p.program_id = ps.program_id 
ORDER BY ... blah blah 

Answer 2

假设有一个名为program_schedule多了一个表，我想补充一个更加入并获得所需的列，下面是例子查询（装出表/列名）：

SELECT 
      program_join.program_join_id, 
      member.member_username, 
      program_join.program_schedule_id, 
      program_schedule.program_name 

      FROM program_join 

       INNER JOIN member ON 
       program_join.member_ID=member.member_ID 
       JOIN program_schedule on program_schedule.id = program_join.program_schedule_id, 
       ORDER BY program_join_id ASC LIMIT $hal, $line";