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当函数的返回值是另一个函数时,无法获得返回的函数的参数名称。这是否是快捷语言的陷阱?在Swift中,没有办法获得返回函数的参数名称?
例如:
func makeTownGrand(budget:Int,condition: (Int)->Bool) -> ((Int,Int)->Int)?
{
guard condition(budget) else {
return nil;
}
func buildRoads(lightsToAdd: Int, toLights: Int) -> Int
{
return toLights+lightsToAdd
}
return buildRoads
}
func evaluateBudget(budget:Int) -> Bool
{
return budget > 10000
}
var stopLights = 0
if let townPlan = makeTownGrand(budget: 30000, condition: evaluateBudget)
{
stopLights = townPlan(3, 8)
}
谨记townPlan
,townPlan(lightsToAdd: 3, toLights: 8)
会更明智的townPlan(3, 8)
,对不对?