谷歌混合（openid + oauth）协议不适用于127.0.0.1

Question

我试图实现谷歌混合协议（oauth over openid）。 而谷歌并没有要求oauth权限（尝试使用Gmail）的问题，只有openid。 我注册在谷歌API控制台：

Client ID for web applications 
Client ID: 248141267047.apps.googleusercontent.com 
Email address:248141267047@developer.gserviceaccount.com 
Client secret: 
Redirect URIs: http://127.0.0.1:8000/oauth2callback 
JavaScript origins:  http://127.0.0.1:8000 

这里是生成的OpenID URL我的Python代码：

class OpenIDOAuthRequest(Extension): 

    ns_alias = 'oauth' 

    def __init__(self, consumer, scope, ns_uri=None): 
     Extension.__init__(self) 
     self.consumer = consumer 
     self.scope = scope 
     self.ns_uri = ns_uri or oauth_ns_uri 

    def getExtensionArgs(self): 
     return { 
      'consumer': self.consumer, 
      'scope': ' '.join(self.scope), 
     } 


def google(): 
     #define google openid url 
     openid_session = {} 
     openid_store = filestore.FileOpenIDStore('.') 
     consumer = Consumer(openid_session, openid_store) 
     openid = u"https://www.google.com/accounts/o8/id" 
     URLS = { 
      'ax_last': "http://axschema.org/namePerson/last", 
      'ax_first': "http://axschema.org/namePerson/first", 
      'ax_email': "http://axschema.org/contact/email", 
      "country":"http://axschema.org/contact/country/home", 
      "timezone":"http://axschema.org/pref/timezone", 
      "language":"http://axschema.org/pref/language", 
      "person":"http://axschema.org/namePerson", 
     } 
     #defining what fields we're going to get 
     ax_request = ax.FetchRequest() 
     for k,v in URLS.iteritems(): 
      ax_request.add(ax.AttrInfo(v, required = True)) 
     oa = OpenIDOAuthRequest("248141267047.apps.googleusercontent.com",["https://mail.google.com/",]) 
     try: 
      authrequest = consumer.begin(openid) 
     except DiscoveryFailure, e: 
      print e 
      print "some errror happened" 
     else: 
      authrequest.addExtension(ax_request) 
      authrequest.addExtension(oa) 



     redirecturl = authrequest.redirectURL("http://127.0.0.1:8000", 
      return_to = "http://127.0.0.1:8000/oauth2callback", 
      immediate=False) 
     print redirecturl 

它会生成以下网址：

https://accounts.google.com/o/openid2/auth?openid.assoc_handle=AMlYA9Vr6Biwp-rCAr4TLbf8CtItR-zr3bs0LT7oYQ3Pakg93ivCS_6C&openid.ax.mode=fetch_request&openid.ax.required=ext0,ext1,ext2,ext3,ext4,ext5,ext6&openid.ax.type.ext0=http://axschema.org/contact/email&openid.ax.type.ext1=http://axschema.org/namePerson&openid.ax.type.ext2=http://axschema.org/namePerson/first&openid.ax.type.ext3=http://axschema.org/pref/timezone&openid.ax.type.ext4=http://axschema.org/pref/language&openid.ax.type.ext5=http://axschema.org/contact/country/home&openid.ax.type.ext6=http://axschema.org/namePerson/last&openid.claimed_id=http://specs.openid.net/auth/2.0/identifier_select&openid.identity=http://specs.openid.net/auth/2.0/identifier_select&openid.mode=checkid_setup&openid.ns=http://specs.openid.net/auth/2.0&openid.ns.ax=http://openid.net/srv/ax/1.0&openid.ns.oauth=http://specs.openid.net/extensions/oauth/1.0&openid.oauth.consumer=248141267047.apps.googleusercontent.com&openid.oauth.scope=https://mail.google.com/&openid.realm=http://127.0.0.1:8000&openid.return_to=http://127.0.0.1:8000/oauth2callback?janrain_nonce%3D2012-05-01T22%253A50%253A33ZUW7vcj 

而且它拥有所有必要的扩展。但是，如果我去这个网址，它不会问我对Gmail的权限。此外，我正在比较来自sanebox.com的类似网址。它按预期工作，要求获得gmail的许可。但我没有看到为什么他们的网址工作，而我的没有任何本质区别。此外，我将我的网址中的127.0.0.1替换为sanebox网址，并将其他部分保留为相同。而且......现在它要求获得gmail的许可。切换回127.0.0.1 - 停止询问。这里是理智的网址：

https://accounts.google.com/o/openid2/auth?openid.assoc_handle=AMlYA9UV4Ud714HHaFJ0fpItabA8v-zw0QuReEPcn61ilJzyFrFia5PO&openid.ax.mode=fetch_request&openid.ax.required=ext0,ext1,ext2,ext3,ext4,ext5,ext6&openid.ax.type.ext0=http://axschema.org/pref/timezone&openid.ax.type.ext1=http://axschema.org/contact/country/home&openid.ax.type.ext2=http://axschema.org/pref/language&openid.ax.type.ext3=http://axschema.org/namePerson/last&openid.ax.type.ext4=http://axschema.org/namePerson/first&openid.ax.type.ext5=http://axschema.org/namePerson&openid.ax.type.ext6=http://axschema.org/contact/email&openid.claimed_id=http://specs.openid.net/auth/2.0/identifier_select&openid.identity=http://specs.openid.net/auth/2.0/identifier_select&openid.mode=checkid_setup&openid.ns=http://specs.openid.net/auth/2.0&openid.ns.ax=http://openid.net/srv/ax/1.0&openid.ns.oauth=http://specs.openid.net/extensions/oauth/1.0&openid.ns.sreg=http://openid.net/extensions/sreg/1.1&openid.oauth.consumer=www.sanebox.com&openid.oauth.scope=https://mail.google.com/+http://www.google.com/m8/feeds&openid.realm=https://www.sanebox.com/&openid.return_to=https://www.sanebox.com/users?_method%3Dpost%26open_id_complete%3D1 

所以我失踪了？为什么它不适用于127.0.0.1，如果我在api控制台中重新生成此url。它和openid一起工作正常。并没有openid与oauth本身很好地工作。但是现在，当我尝试在openid上使用oauth时，它并没有要求我向gmail发送许可。

Answer 1

我已经运行了PHP，ASP，DOT NET代码，它们运行得非常好，因此确保python应用程序也能正常运行。您必须更改默认应用程序。首先运行他们提供的默认应用程序并尝试更改。如果默认的应用程序不起作用，那么也可以打开一个错误报告给谷歌。