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试图结合下拉字段到身体这里发送的电子邮件是我的代码。只返回1下拉。想要将消息和消息1从下拉列表中合并到$ comment字段尝试了多种在线解决方案,但似乎找不到可行的解决方案。请帮助PHP电子邮件结合字段发送电子邮件
$admin_email = "[email protected]";
$email = $_REQUEST['email'];
$subject = "Beverage Request";
$comment = $_REQUEST['message']);
//send email
mail($admin_email, "$subject", $comment, "From:" . $email);
//Email response
echo "Thank you for contacting us!";
}
//if "email" variable is not filled out, display the form
else {
?>
<form method= "post" action= "<?php echo $_SERVER [ 'PHP_SELF' ] ;?>" />
<table>
<tr>
<td>Email: <input name="email" type="text" /><br />
</td>
</tr>
<tr>
<td>Beverage Choice </td>
<td><select id="message1" Name="message1">
<option value="Beer">Beer</option>
<option value="Wine">Wine</option>
<option value="Cidar">Cidar</option>
</select>
</td>
<td>Size of bottle </td>
<td><select id="message" Name="message">
<option value="Sample">Sample</option>
<option value="12 oz">12 oz</option>
<option value="22 oz">22 oz</option>
<option value="32 oz">32 oz</option>
</select>
</td>
</tr>
<tr>
在我看来,因为这篇文章会回答你的问题[html-php-form-input-as-array](https://stackoverflow.com/questions/20184670/html-php-form-input-as-array ) – chilly
你可以阅读$ _POST ['message1'],就像你做'消息'对应。顺便说一句:你应该检查$ _POST ['email']是否真的包含一个邮件地址(并且不会超过)。否则,有人可以接管你的邮件表格并发送他自己的邮件,使用你的服务器发送垃圾邮件 –
这里出现语法错误 –