2015-10-05 162 views
1

我有以下情节:如何拟合线性趋势线到Libre Office Calc中的半对数散点图?

enter image description here

,我想以适应线性趋势线的数据,所以可在进一步计算中使用的斜率。然而,当我尝试以适应线性趋势线,我得到这个: enter image description here

如果我适合功率趋势线,然后我得到了R^2过.999,但趋势线是没用的,我...是否任何人都知道完成这个的正确方法?

编辑:这里是CSV格式

Iron in Copper,,,Cobalt in Copper,,,Nickel in Copper,, 
T (oC),D (cm2/sec),1/T (1/K),T (oC),D (cm2/sec),1/T (1/K),T (oC),D (cm2/sec),1/T (1/K) 
1074,5.65E-09,0.0007423078,1077,3.43E-09,0.0007406584,1076,1.98E-09,0.0007412074 
974,1.11E-09,0.0008018282,983,7.64E-10,0.0007960833,980,3.57E-10,0.0007979891 
895,2.86E-09,0.0008560544,904,1.77E-10,0.0008495094,900,7.87E-11,0.0008524059 
830,7.80E-11,0.000906495,844,5.09E-11,0.0008951349,847,2.61E-11,0.0008927376 
780,2.67E-11,0.0009495324,793,1.65E-11,0.0009379543,791,6.82E-12,0.0009397171 
719,6.55E-12,0.0010079121,744,5.31E-12,0.0009831392,743,1.90E-12,0.0009841067 
,,,701,1.76E-12,0.001026536,,, 
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@tohuwawohu发布 – DrJPepper

+1

您的y轴是对数坐标。所以肯定线性趋势线看起来像你看到它。 –

回答

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嗯数据 - 这些价值观,我得到:

enter image description here

趋势线似乎对我罚款? (对不起,没有答案,但我不能把图表放入评论中...)

+1

谢谢你的回应;我想出了这个问题。我误解了这个任务,实际上我应该使用指数趋势线。 – DrJPepper