我正在使用ANTLR4语法来解析SQLite查询。但是,词法分析器正在返回一个空的标记流,即使我正在使用简单的选择查询。ANTLR 4提供空令牌流的SQLite语法
我们得到以下错误:
Exception in thread "main" java.lang.IllegalStateException: nextToken requires a non-null input stream.
at org.antlr.v4.runtime.Lexer.nextToken(Lexer.java:138)
at org.antlr.v4.runtime.BufferedTokenStream.fetch(BufferedTokenStream.java:186)
at org.antlr.v4.runtime.BufferedTokenStream.sync(BufferedTokenStream.java:169)
at org.antlr.v4.runtime.BufferedTokenStream.setup(BufferedTokenStream.java:271)
at org.antlr.v4.runtime.BufferedTokenStream.lazyInit(BufferedTokenStream.java:266)
at org.antlr.v4.runtime.CommonTokenStream.LT(CommonTokenStream.java:116)
at org.antlr.v4.runtime.Parser.enterRecursionRule(Parser.java:677)
at antlr.antlr4.SQLIte.SQLiteParser.expr(SQLiteParser.java:5109)
at antlr.antlr4.SQLIte.SQLiteParser.expr(SQLiteParser.java:5100)
at antlr.antlr4.SQLIte.LexerParser.main(LexerParser.java:38)
这是main.java类的代码:
import antlr.antlr4.SQLIte.*;
import antlr.antlr4.SQLIte.SQLiteParser.ExprContext;
import org.antlr.v4.runtime.ANTLRInputStream;
import org.antlr.v4.runtime.CommonTokenStream;
import org.antlr.v4.runtime.misc.NotNull;
import org.antlr.v4.runtime.tree.ParseTree;
import org.antlr.v4.runtime.tree.ParseTreeWalker;
import java.io.ByteArrayInputStream;
import java.io.InputStream;
import java.nio.charset.StandardCharsets;
import java.util.ArrayList;
import java.util.List;
public class LexerParser {
public static void main(String[] args) throws Exception {
// The list that will hold our function names.
final List<String> functionNames = new ArrayList<String>();
// The select-statement to be parsed.
String sql = "SELECT * FROM table";
// Create a lexer and parser for the input.
InputStream stream = new ByteArrayInputStream(sql.getBytes(StandardCharsets.UTF_8), 0, 0);
ANTLRInputStream antlrTemp = new ANTLRInputStream(stream);
SQLiteLexer lexer = new SQLiteLexer(antlrTemp);
// SQLiteLexer lexer = new SQLiteLexer(antlrTemp);
CommonTokenStream cts = new CommonTokenStream(lexer);
System.out.print(cts.getTokens());
SQLiteParser parser = new SQLiteParser(cts);
ExprContext theExpr = parser.expr();
System.out.println("found expr " + theExpr.toString());
我要去哪里错了吗?
为什么不直接使用'new ANTLRInputStream(sql)'? – 2015-04-06 11:47:06
@LucasTrzesniewski - 这给出了同样的错误。词法分析器中的我的令牌流为空。输出[]当我使用 CommonTokenStream cts = new CommonTokenStream(lexer); System.out.print(cts.getTokens()); – user3898179 2015-04-06 11:50:22
好的,我看了一下语法 - 你应该使用'parser.parse()'而不是'parser.expr()' – 2015-04-06 11:52:53