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我有一个表插入从选择返回另一个值
|| *content_id* || *content_value* || *content_const* || *language_language_id* ||
|| 1 || title_1 || heading_1 || 1 ||
|| 2 || title_2 || heading_2 || 1 ||
|| 23 || subtitle_1 || sub_1 || 1 ||
|| 24 || subtitle_2 || sub_2 || 1 ||
|| 50 || title_1 || heading_1 || 2 ||
|| 51 || title_2 || heading_2 || 2 ||
|| 48 || title_2 || heading_2 || 3 ||
|| 53 || title_1 || heading_1 || 3 ||
我需要插回表LANGUAGE_ID究竟存在于表中的值(在这种情况下,id为2和3)什么什么我添加任何语言ID。这是做什么的正确方法?
我需要的结果:
|| *content_id* || *content_value* || *content_const* || *language_language_id* ||
|| 1 || title_1 || heading_1 || 1 ||
|| 2 || title_2 || heading_2 || 1 ||
|| 23 || subtitle_1 || sub_1 || 1 ||
|| 24 || subtitle_2 || sub_2 || 3 ||
|| 48 || title_2 || heading_2 || 3 ||
|| 50 || title_1 || heading_1 || 2 ||
|| 51 || title_2 || heading_2 || 2 ||
|| 53 || title_1 || heading_1 || 3 ||
|| 62 || subtitle_1 || sub_1 || 1 ||
|| 63 || subtitle_1 || sub_1 || 2 ||
|| 64 || subtitle_1 || sub_1 || 2 ||
|| 65 || subtitle_1 || sub_1 || 3 ||
我有一个查询什么给我很好的结果没有语言ID。 SELECT * FROM .content GROUP BY .content.content_const HAVING COUNT(.content.content_const) = 1
,但我需要它插回与其他语言ID ... :( 谢谢你的帮助