stackflow新增,我希望我的问题可以帮助其他python新手。初学者:用elif控制流和语法错误
我试图创建一个执行程序如下:1。 == secret_num产生1-10
2之间的随机#询问用户猜测1-10 3之间用这个号码,如果猜测= = secret_num向他们表示祝贺,并提供 4.帐户重复猜测 5.让他们知道,如果猜测是太高或太低
我知道这是ABC的东西为它花了猜测number_guesses的数量(减去任何重复的猜测)很多人,但我有语法,缩进和控制流程的典型新程序员问题。现在我得到了elif guess == secret num的语法。否则,我无法获得此代码来解释重复以挽救我的生命。我将不胜感激任何帮助。谢谢 。
import random
def game():
# generate a random number between 1 -100 and initiate repeat guess list
secret_num=random.randint(1,10)
# initiate duplicate list and number of guesses
already_guesses = []
number_guesses = 0
while True:
# ask for user guess
guess = int(input('Guess a number from 1-10> '))
# help with guesses and announce if it is correct number!
# catch someone if they submit the same number
if guess in already_guesses:
print ("You already guessed that number, try again")
already_guesses.append(guess)
number_guesses += 1
elif guess == secret_num:
print("whooohoo! you guessed it, my number is {}".format(secret_num))
print("It took you {} guesses".format(number_guesses - len([already_guesses])))
break
elif guess < secret_num:
print("You\'re getting hot, try a higher number")
else:
guess > secret_num
print("You\'re cold, try a lower number")
# ask if they want to play again
else:
play_again = input("Do you wanna play again? y/n")
if play_again != 'n':
game()
else:
print("Bah Bye!")
game()
的上面两行需要缩进。 – neil