2014-10-07 58 views
0

我正在尝试编写一个实用程序,让我可以根据配置文件将命令设置为在unix shell中运行。从本质上讲,我希望能够给一个[Command List]和预期[Response List]。这里是我的配置文件中的一个例子:使用ConfigParser读取字符串作为配置值

# Command File 
# List of commands to be carried out for each host listed in `veri.serv.cfg` 

[Command List] 
; T server 
nc -zw1 159.1.1.1 9988 | gawk '{print $7}' 

; P Server 
nc -zw1 sup.serv.com 8050 | gawk '{print $7}' 

; G L Service 
nc -zw1 hi.serv.com 80 | gawk '{print $7}' 

; L and N Hosts 
nc -zw1 l.serv.com 80 | gawk '{print $7}' 
nc -zw1 ln.serv.com 443 | gawk '{print $7}' 
nc -zw1 llnn.serv.com 443 | gawk '{print $7}' 

然而,当我试图解析使用parser.items('Command List')它,我得到:

File "veri.py", line 22, in <module> 
    print subConfigParser.read(os.path.join(relativeRunPath, 'veri.cfg')) 
    File "/usr/lib/python2.7/ConfigParser.py", line 305, in read 
    self._read(fp, filename) 
    File "/usr/lib/python2.7/ConfigParser.py", line 546, in _read 
    raise e 
ConfigParser.ParsingError: File contains parsing errors 

[line 6]: "nc -zw1 159.1.1.1 9988 | gawk '{print $7}'\n" 
[line 9]: "nc -zw1 sup.serv.com 8050 | gawk '{print $7}'\n" 
[line 12]: "nc -zw1 hi.serv.com 80 | gawk '{print $7}'\n" 
[line 15]: "nc -zw1 l.serv.com 80 | gawk '{print $7}'\n" 
[line 16]: "nc -zw1 ln.serv.com 443 | gawk '{print $7}'\n" 
[line 17]: "nc -zw1 llnn.serv.com 443 | gawk '{print $7}'\n" 

使用SafeConfigParser作为值时,我不能以完整的字符串读取吗?

完整文件:

#! /usr/bin/python25 
import os 
import ConfigParser 

# --- sudo consts --- # 
# relative path, regardless of where we're executing from 
RELATIVE_PATH = os.path.abspath(os.path.dirname(__file__)) 
BASE_SERVER_FILE = os.path.join(RELATIVE_PATH, 'cfg', 'veri.serv.cfg') 
BASE_CONFIG_FILE = os.path.join(RELATIVE_PATH, 'cfg', 'veri.base.cfg') 
# --- end consts --- # 

baseConfigParser = ConfigParser.SafeConfigParser() 
baseConfigParser.read(BASE_CONFIG_FILE) 
runlist = baseConfigParser.get('Config List', 'runlist').strip().split("\n") 
print runlist 

for subDir in runlist: 
    print subDir 
    relativeRunPath = os.path.join(RELATIVE_PATH, subDir) 
    subConfigParser = ConfigParser.SafeConfigParser() 
    subConfigParser.read(os.path.join(relativeRunPath, 'veri.cfg')) 
    print subConfigParser.items('Command List')   ###### <<< Error Here 
    if os.path.isfile(os.path.join(relativeRunPath, 'veri.serv.cfg')): 
     subServSpecified = true 
     subServConfigParser = ConfigParser.SafeConfigParser() 
     subServConfigParser.read(os.path.join(relativeRunPath, 'veri.serv.cfg')) 
     print subServConfigParser.get('Config List', 'runlist') 

回答

1

您的配置文件没有使用有效的格式ConfigParser。它需要一系列的部分,随后命名的选项,如

[T server] 
commands = nc -zw1 159.1.1.1 9988 | gawk '{print $7}' 

[P Server] 
commands = nc -zw1 sup.serv.com 8050 | gawk '{print $7}' 

[G L Service] 
commands = nc -zw1 hi.serv.com 80 | gawk '{print $7}' 

[L and N Hosts] 
commands = nc -zw1 l.serv.com 80 | gawk '{print $7}' 
    nc -zw1 ln.serv.com 443 | gawk '{print $7}' 
    nc -zw1 llnn.serv.com 443 | gawk '{print $7}' 

然后,您可以获取值

>>> from ConfigParser import SafeConfigParser 
>>> parser = SafeConfigParser() 
>>> parser.read('myconfig.ini') 
['myconfig.ini'] 
>>> for section in parser.sections(): 
...  print 'section', section 
...  for option in parser.options(section): 
...    print parser.get(section, option) 
... 
section T server 
nc -zw1 159.1.1.1 9988 | gawk '{print $7}' 
section P Server 
nc -zw1 sup.serv.com 8050 | gawk '{print $7}'                                 
section G L Service                                        
nc -zw1 hi.serv.com 80 | gawk '{print $7}'                                  
section L and N Hosts                                       
nc -zw1 l.serv.com 80 | gawk '{print $7}'                                  
nc -zw1 ln.serv.com 443 | gawk '{print $7}'                                  
nc -zw1 llnn.serv.com 443 | gawk '{print $7}'                                 
>>>                     
+0

嗯,这是不幸的 - 所以没有办法没有一个选项,值对? – MrDuk 2014-10-07 18:38:57

+0

如果你喜欢你的格式到一个标准的ini文件,你可以编写你自己的解析器。您会过滤掉以“;”开头的行或者是空白的,请扫描“[xx]”并将其余行添加到您自己的字典中。 – tdelaney 2014-10-07 18:46:59