SQL Server中的XML子节点追加到父节点

我需要有一个脚本可以插入/新的XML子节点追加到一个预先存在的XML父节点。SQL Server中的XML子节点追加到父节点

--New child nodes 
DECLARE @XMLChildData XML 
SET @XMLChildData = ' 
<Persons> 
    <Person> 
     <Firstname>Gary</Firstname> 
     <Surname>Smith</Surname> 
     <Telephone>0115547899</Telephone> 
     <Address> 
      <AddressLine>1 Church Lane</AddressLine> 
      <AddressLine>Rosebank</AddressLine> 
      <AddressLine>Houghton</AddressLine> 
      <AddressLine>South Africa</AddressLine> 
     </Address> 
    </Person> 
    <Person> 
     <Firstname>Wayne</Firstname> 
     <Surname>Farmey</Surname> 
     <Telephone>0117453269</Telephone> 
     <Address> 
      <AddressLine>51 Oak Street</AddressLine> 
      <AddressLine>Rivionia</AddressLine> 
      <AddressLine>Sandton</AddressLine> 
      <AddressLine>South Africa</AddressLine> 
     </Address> 
    </Person> 
    <Person> 
     <Firstname>Mark</Firstname> 
     <Surname>Jones</Surname> 
     <Telephone>0119854741</Telephone> 
     <Address> 
      <AddressLine>4 Arum Lane</AddressLine> 
      <AddressLine>Glen Hazel</AddressLine> 
      <AddressLine>Johannesburg</AddressLine> 
      <AddressLine>South Africa</AddressLine> 
     </Address> 
    </Person> 
</Persons>' 

--Existing parent node 
DECLARE @XMLParentData XML 
SET @XMLParentData = ' 
<Persons> 
    <Person> 
     <Firstname>Sarah</Firstname> 
     <Surname>Gray</Surname> 
     <Telephone>0113265874</Telephone> 
     <Address> 
      <AddressLine>78 Emerl Aveune</AddressLine> 
      <AddressLine>Fourways</AddressLine> 
      <AddressLine>Sandton</AddressLine> 
      <AddressLine>South Africa</AddressLine> 
     </Address> 
    </Person> 
    <Person> 
     <Firstname>Jenna</Firstname> 
     <Surname>Reed</Surname> 
     <Telephone>0114781102</Telephone> 
     <Address> 
      <AddressLine>6 Park Lane</AddressLine> 
      <AddressLine>Parkhurst</AddressLine> 
      <AddressLine>Rosebank</AddressLine> 
      <AddressLine>South Africa</AddressLine> 
     </Address> 
    </Person> 
    <Person> 
     <Firstname>Mike</Firstname> 
     <Surname>Wilke</Surname> 
     <Telephone>0116532003</Telephone> 
     <Address> 
      <AddressLine>22 High Road</AddressLine> 
      <AddressLine>Modderfontein</AddressLine> 
      <AddressLine>Edenvale</AddressLine> 
      <AddressLine>South Africa</AddressLine> 
     </Address> 
    </Person> 
</Persons>'

我想最终的结果是：

<Persons> 
    <Person> 
     <Firstname>Sarah</Firstname> 
     <Surname>Gray</Surname> 
     <Telephone>0113265874</Telephone> 
     <Address> 
      <AddressLine>78 Emerl Aveune</AddressLine> 
      <AddressLine>Fourways</AddressLine> 
      <AddressLine>Sandton</AddressLine> 
      <AddressLine>South Africa</AddressLine> 
     </Address> 
    </Person> 
    <Person> 
     <Firstname>Jenna</Firstname> 
     <Surname>Reed</Surname> 
     <Telephone>0114781102</Telephone> 
     <Address> 
      <AddressLine>6 Park Lane</AddressLine> 
      <AddressLine>Parkhurst</AddressLine> 
      <AddressLine>Rosebank</AddressLine> 
      <AddressLine>South Africa</AddressLine> 
     </Address> 
    </Person> 
    <Person> 
     <Firstname>Mike</Firstname> 
     <Surname>Wilke</Surname> 
     <Telephone>0116532003</Telephone> 
     <Address> 
      <AddressLine>22 High Road</AddressLine> 
      <AddressLine>Modderfontein</AddressLine> 
      <AddressLine>Edenvale</AddressLine> 
      <AddressLine>South Africa</AddressLine> 
     </Address> 
    </Person> 
    <Person> 
     <Firstname>Gary</Firstname> 
     <Surname>Smith</Surname> 
     <Telephone>0115547899</Telephone> 
     <Address> 
      <AddressLine>1 Church Lane</AddressLine> 
      <AddressLine>Rosebank</AddressLine> 
      <AddressLine>Houghton</AddressLine> 
      <AddressLine>South Africa</AddressLine> 
     </Address> 
    </Person> 
    <Person> 
     <Firstname>Wayne</Firstname> 
     <Surname>Farmey</Surname> 
     <Telephone>0117453269</Telephone> 
     <Address> 
      <AddressLine>51 Oak Street</AddressLine> 
      <AddressLine>Rivionia</AddressLine> 
      <AddressLine>Sandton</AddressLine> 
      <AddressLine>South Africa</AddressLine> 
     </Address> 
    </Person> 
    <Person> 
     <Firstname>Mark</Firstname> 
     <Surname>Jones</Surname> 
     <Telephone>0119854741</Telephone> 
     <Address> 
      <AddressLine>4 Arum Lane</AddressLine> 
      <AddressLine>Glen Hazel</AddressLine> 
      <AddressLine>Johannesburg</AddressLine> 
      <AddressLine>South Africa</AddressLine> 
     </Address> 
    </Person> 
</Persons>

我知道我需要使用.modify（），但我不知道如何通过子节点进行迭代，并插入/追加每个小孩"<person>"节点放入父节点"<persons>"。

我认为这将需要类似的东西如下

SET @XMLParentData.modify(' 
    insert  
     (
      sql:variable("@XMLChildData") 
     ) 
    after 
     (/Person[1]/Person[1]) 
') 

SELECT @XMLData

来源

2014-10-20 user3917837

从提取的@XMLChildData节点Person到一个单独的变量，并添加到@XMLParentData的Persons节点。

DECLARE @PersonList XML 

SET @PersonList = @XMLChildData.query('Persons/*') 

SET @XMLParentData.modify('insert sql:variable("@PersonList") as last into /Persons[1]') 

SELECT @XMLParentData

另一种方法是提取这两个变量的Person节点和重建使用FOR XML PATH的Persons节点。

SET @XMLParentData = (
        SELECT @XMLParentData.query('/Persons/Person'), 
          @XMLChildData.query('/Persons/Person') 
        FOR XML PATH(''), ROOT('Persons'), TYPE 
        )

来源

2014-10-21 06:11:11

感谢的Mikael，如果我把你的第一个代码片断我有同样的问题与建议Bummi，是我似乎从附加子节点的列表到父列表。我希望只有父节点xml，其根节点为，并且只将子节点xml中的节点附加到父节点xml中。如果我把你的第二个代码片段按预期工作。我怎样才能达到你的第一个代码片段所需的结果。我想了解我做错了什么，所以我可能会更好。 – user3917837 2014-10-21 07:03:57

@ user3917837第一个按预期工作。您可能忘记更改您在'sql：variable'中使用的变量。看看这个[SQL Fiddle]（http://sqlfiddle.com/#!3/d41d8/40302）。 – 2014-10-21 07:30:41

对不起......你是对的。谢谢Mikael – user3917837 2014-10-21 07:37:34

SQL Server中的XML子节点追加到父节点

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