从正则表达式

Question

提取匹配给定一个字符串

""Being Ordered Around by You Makes Me Really Angry Somehow!!!" "Whaddaya Mean, 'Somehow'!!?"" 
""Omae ni Meirei Sareru no wa Nanka Haratatsu!!!" "Nankatte Nani!!?"" 

我如何可以提取各组双引号（包括其中的双引号），这样我得到两个独立的串像之间的字符串：

"Being Ordered Around by You Makes Me Really Angry Somehow!!!" "Whaddaya Mean, 'Somehow'!!?" 

和

"Omae ni Meirei Sareru no wa Nanka Haratatsu!!!" "Nankatte Nani!!?" 

我目前使用的正则表达式是"(.*)(.*)"并根据匹配没关系此工具

我的问题是提取两场比赛作为单独的字符串。

var pattern = new Regex(@"""(.*)(.*)""", RegexOptions.None); 
var matches = pattern.Matches(text); 

matches不包含两个元素。我究竟做错了什么？

Answer 1

尝试使用Regex.Match代替Matches，而这正则表达式

"("[^"]*")[^"]*("[^"]*")" 

它相匹配的"，捕获跟随"和任何达，和包括，下"。然后它会匹配下一个"。然后它重复 - 捕获以下"和任何事情，包括下一个"。最后它匹配终止"。这两个字符串，包括其周围的报价是捕获组1 & 2.

事情是这样的：

string s1 = "\"\"Being Ordered Around by You Makes Me Really Angry Somehow!!!\" \"Whaddaya Mean, 'Somehow'!!?\"\"", 
      s2 = "\"\"Omae ni Meirei Sareru no wa Nanka Haratatsu!!!\" \"Nankatte Nani!!?\"\""; 

    Console.WriteLine("Before 1 : " + s1); 
    Console.WriteLine("Before 2 : " + s2); 

    Regex r = new Regex("\"(\"[^\"]*\")[^\"]*(\"[^\"]*\")\""); 
    Match m = r.Match(s1); 
    Console.WriteLine("After 1.1 : " + m.Groups[1].Value); 
    Console.WriteLine("After 1.2 : " + m.Groups[2].Value); 

    m = r.Match(s2); 
    Console.WriteLine("After 2.1 : " + m.Groups[1].Value); 
    Console.WriteLine("After 2.2 : " + m.Groups[2].Value); 

See it here at ideone。

Answer 2

您可以尝试this regex

("{2}.+?"{2}) 

并反复对MatchCollection类提供匹配。