修改的2个字节

Question

在C＃10位，我将如何去设置2个字节，其中第一个10位代表一个十进制值和下一个6代表不同的十进制值？

因此，如果第一个值是“8”（前10个比特）和第二“2”（剩余6个比特），我需要“0000001000 000010”结束了一个字节数组内。

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Answer 1

UInt16 val1 = 8; 
UInt16 val2 = 2; 
UInt16 combined = (UInt16)((val1 << 6) | val2); 

如果你需要在一个字节数组，你可以传递结果到BitConverter.GetBytes method。

byte[] array = BitConverter.GetBytes(combined); 

Answer 2

int val1 = 8; 
int val2 = 2; 

// First byte contains all but the 2 least significant bits from the first value. 
byte byte1 = (byte)(val1 >> 2); 

// Second byte contains the 2 least significant bits from the first value, 
// shifted 6 bits left to become the 2 most significant bits of the byte, 
// followed by the (at most 6) bits of the second value. 
byte byte2 = (byte)((val1 & 4) << 6 | val2); 

byte[] bytes = new byte[] { byte1, byte2 }; 

// Just for verification. 
string s = 
    Convert.ToString(byte1, 2).PadLeft(8, '0') + " " + 
    Convert.ToString(byte2, 2).PadLeft(8, '0'); 

Answer 3

不占任何溢出：

private static byte[] amend(int a, int b) 
{ 
    // Combine the datum into a 16 bits integer 
    var c = (ushort) ((a << 6) | (b)); 
    // Fragment the Int to bytes 
    var ret = new byte[2]; 
    ret[0] = (byte) (c >> 8); 
    ret[1] = (byte) (c); 

    return ret; 
} 

Answer 4

ushort value = (8 << 6) | 2; 
byte[] bytes = BitConverter.GetBytes(value);