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我在我的网站上有一个flickr供稿,并且我想在每张图片下添加一个Pinterest“Pin-it”按钮。如何构建Flickr Feed的Pin-It按钮?
这里的饲料脚本:
<script>
$.getJSON('http://api.flickr.com/services/feeds/photoset.gne?set=72157647581330595&[email protected]&lang=en-us&format=json&jsoncallback=?', function(data) {
$.each(data.items, function(i,item) {
var large = (item.media.m).replace('_m.jpg', '_b.jpg');
if(i <= 20){
$('#list').append('<li class="picture"><a class="slide-img" data-lightbox="engagement" href="' + large + '"><img src="' + large + '"/></a></li>');
}
});
});
</script>
我想将
<a href="http://www.pinterest.com/pin/create/button/?url=http%3A%2F%2Fwww.pushpinevents.com&media=http%3A%2F%2Ffarm4.staticflickr.com%2F3838%2F15273469932_0c3ceaeb96_b.jpg&description=%40PushPin%20Events" data-pin-do="buttonPin" data-pin-config="beside"><img src="//assets.pinterest.com/images/pidgets/pinit_fg_en_rect_gray_20.png" /></a>
代码添加到.append
方法并替换URL字符串与图像链接。
我最好的猜测是我需要从flickr网址定义一个变量,并用%2F等替换%3F':'。
因此,像:
var link = (large).replace('/', '%3F');
问题1 - 我怎样才能更换一个.replace
方法多个字符?
说的已定义后,我的代码下挥杆看起来像:
<script>
$.getJSON('http://api.flickr.com/services/feeds/photoset.gne?set=72157647581330595&[email protected]&lang=en-us&format=json&jsoncallback=?', function(data) {
$.each(data.items, function(i,item) {
var large = (item.media.m).replace('_m.jpg', '_b.jpg');
if(i <= 20){
$('#list').append('<li class="picture"><a class="slide-img" data-lightbox="engagement" href="' + large + '"><img src="' + large + '"/></a></li><br><a href="http://www.pinterest.com/pin/create/button/?url=http%3A%2F%2Fwww.pushpinevents.com&media='+link+'" data-pin-do="buttonPin" data-pin-config="beside">Pin It!</a>');
}
});
});
</script>
问题2 - 这是做到这一点的最有效方法是什么?