无法使用pdo输出到csv

Question

我正在从数据库中检索数据并将数据下载到csv文件中。该功能正常工作，但正在下载的csv文件也包含页面源代码，我不知道为什么会发生这种情况并且一直在尝试很长时间。我希望有人能帮助我。下面是源代码：

public function exportSalesCsv() 
{ 

$conn = new PDO('mysql:host=' . config::get('mysql/host') . ';dbname=' . config::get('mysql/db'), config::get('mysql/username'), config::get('mysql/password')); 
$sql = "SELECT 
      CONCAT(u.name, ' ', u.surname) AS salesPerson, 
      t.initiation_timestamp AS saleDate, 
      t.customer_account_id AS customerAccount, 
      tt.transaction_type AS transactionType, 
      r.resource_unique_value AS soldResource, 
      CONCAT(rb.resource_brand, 
        ' ', 
        rm.resource_model, 
        ' ', 
        rt.resource_type) AS resourceModel, 
      r.voucher_value_id as value 
     FROM 
      ims.transactions t 
       INNER JOIN 
      ims.resources r ON t.resource_id = r.resource_id 
       INNER JOIN 
      ims.resource_models rm ON r.resource_model_id = rm.resource_model_id 
       INNER JOIN 
      ims.resource_brands rb ON rm.resource_brand_id = rb.resource_brand_id 
       INNER JOIN 
      ims.resource_types rt ON rm.resource_type_id = rt.resource_type_id 
       INNER JOIN 
      ims.users u ON t.uid = u.uid 
       INNER JOIN 
      ims.transaction_types tt ON t.transaction_type_id = tt.transaction_type_id 
     WHERE 
      t.transaction_type_id = 3 
       AND YEAR(t.initiation_timestamp) = YEAR(CURDATE()) 
     UNION SELECT 
      CONCAT(u.name, ' ', u.surname) AS salesPerson, 
      o.closing_timestamp AS saleDate, 
      o.customer_id AS customerAccount, 
      tt.transaction_type AS transactionType, 
      r.resource_unique_value AS soldResource, 
      CONCAT(rb.resource_brand, 
        ' ', 
        rm.resource_model, 
        ' ', 
        rt.resource_type) AS resourceModel, 
      r.voucher_value_id as value 
     FROM 
      orders o 
       INNER JOIN 
      ims.users u ON o.initiation_uid = u.uid 
       INNER JOIN 
      ims.transaction_types tt ON o.order_type_id = tt.transaction_type_id 
       INNER JOIN 
      ims.resources r ON o.resource_id = r.resource_id 
       INNER JOIN 
      ims.resource_models rm ON r.resource_model_id = rm.resource_model_id 
       INNER JOIN 
      ims.resource_brands rb ON rm.resource_brand_id = rb.resource_brand_id 
       INNER JOIN 
      ims.resource_types rt ON rm.resource_type_id = rt.resource_type_id 
     WHERE 
      o.order_type_id = 4 
       AND order_status_id = 1 
       AND YEAR(o.closing_timestamp) = YEAR(CURDATE())"; 
$results = $conn->query($sql); 

$response = implode(",", array('salesPerson','saleDate','customerAccount','transactionType','soldResource','resourceModel','value')); 
$response .= "\n"; 

foreach($results as $row) 
{ 
    $response .= implode(",",array($row['salesPerson'], $row['saleDate'], $row['customerAccount'], $row['transactionType'], $row['soldResource'], $row['resourceModel'], $row[escape('value')])); 
    $response .= "\n"; 
} 

header('Content-type: text/csv'); 
header('Content-disposition: attachment;filename=salesExport.csv'); 

echo $response; 

return; 

}

下面的截图说明我的意思：Click Here

，这里是我是如何调用方法：

<?php 
require_once 'core/init.php'; 
include_once ("header.php"); 

if ($user->isLoggedIn()){ 

//check if user has permission 
if ($user->hasPermission('reports') || $user->hasPermission('allAccess')){ 

    $inventory = new inventory(); 

    if(isset($_POST['exportSalesCsv'])){ 

     $inventory->exportSalesCsv(); 

    }... 

Answer 1

您的脚本只将文件保存到磁盘并填充数据，但不会在回复中返回

一个解决方案，如果创建的文件可以通过apache/nginx服务器访问，您可以重定向到它。将此添加到函数的末尾。

header('Location: ' . $url_to_file); 
return; 

另一种解决方案是不打印到文件，而是写一个变量，并与头部返回它返回一个CSV文件，这样浏览器将其解释为csv文件：

$results = $conn->query($sql); 

$response = implode(",", array('salesPerson','saleDate','customerAccount','transactionType','soldResource')); 
$response .= "\n"; 

foreach($results as $row) 
{ 
    $response .= implode(",",array($row['salesPerson'], $row['saleDate'], $row['customerAccount'], $row['transactionType'], $row['soldResource'])); 
    $response .= "\n"; 
} 

header('Content-type: text/csv'); 
header('Content-disposition: attachment;filename=' . strtotime("now") . '.csv'); 

echo $response; 

return;