我有一个包含自定义视图中的XML布局:无效()不更改自定义视图的内容立即
<LinearLayout
android:layout_width="fill_parent"
android:layout_height="0dip"
android:orientation="vertical"
android:layout_weight="50"
>
<org.example.sudoku.PuzzleView
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:background="@drawable/puzzlebackground"
android:id="@+id/puzzleId"/>
</LinearLayout>
我有一个的活动,设置此布局的内容,则调用一个对话框,用户输入,然后在PuzzleView中调用一个函数来最终更改PuzzleView的内容。问题在于,在Dialog解散之后,该更改没有被重新绘制。相反,它会重新绘制来自用户的下一个其他输入。 下面是一些代码片断,可以帮助你:
Game.java:
// ...
public void showKeypadOrError(int x, int y)
{
int tiles[] = getUsedTiles(x,y);
if (tiles.length == 9)
{
Toast toast = Toast.makeText(this, R.string.no_moves_label, Toast.LENGTH_SHORT);
toast.setGravity(Gravity.CENTER, 0, 0);
toast.show();
}else
{
Log.d(TAG, "showKeypad: used=" + toPuzzleString(tiles));
Dialog v = new Keypad(this, this.puzzleView, x, y);
v.show();
}
}
public void setTile(int x, int y, int value) {
puzzle[y * 9 + x] = value;
}
Keypad.java:
private void setListeners()
{
for (int i = 0; i < keys.length; i++)
{
final int t = i + 1;
keys[i].setOnClickListener(new View.OnClickListener() {
public void onClick(View v)
{
returnResult(t);
}
});
}
}
private void returnResult(int tile)
{
puzzleView.setSelectedTile(selX, selY, tile);
puzzleView.invalidate();
dismiss();
}
最后,PuzzleView.java
public void setSelectedTile(int X, int Y, int tile) {
game.setTile(X, Y, tile);
//this.invalidate();// may change hints
}
我发现了一个类似于我的问题的问题,但我无法弄清楚什么是解决方案离子:
How to invalidate() on return from a dialog?
非常感谢您对您的帮助! 编辑:添加更多的代码 - 希望这帮助: PuzzleView.java
// Handle input in touch mode
@Override
public boolean onTouchEvent(MotionEvent event) {
if (event.getAction() != MotionEvent.ACTION_DOWN) {
return super.onTouchEvent(event);
}
// Allow player to choose the tile that defined by game
// But only allow the user to modify the tiles that are blank
select((int) (event.getX()/width),
(int) (event.getY()/height));
int[] predefined = new int[81];
// Get the tile that are not blank (predefined by game)
predefined = game.getPredefinedTileFromPuzzle();
// Check if the selected tile is whether predefined or not
if (predefined[selY * 9 + selX] == 1) {
return true;
}
//Call the Dialog input from Game.java
game.showKeypadOrError(selX, selY);
Log.i(TAG, "Right before terminate onTouchEvent()");
return true;
}
只是用于测试的缘故,做'returnResult(4)'地方比别的clicklistener其他...硬编码的瓷砖值,看看是否无效发生... – Ronnie 2012-04-23 13:58:45