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我正在写一个脚本,需要存档文件夹和文件里面,但我不知道如何做到这一点,如果有一个文件夹内的另一个文件夹。我将通过实例讲解,让规范工作zipArchive如何保存文件夹中的文件夹
Warning: ZipArchive::close(): Read error: Is a directory in /путь до скрипта/public_html/crm/drive/drive.php on line 102
Folder +
File1
File2
And so on (so it works)
But does not want to work like that
Folder +
File1
FOLDER (this does not work)
的问题是如何让这个如果脚本中所看到的文件夹,还下载了如果我看到该文件夹内的文件夹也分别下载文件夹中的文件?这里是我的脚本
if (isset($_POST['createPath'])) {//Check that the button is clicked
$zip = new ZipArchive(); // Create an archive
$zip_name = time().".zip"; // file name
if ($zip->open($zip_name, ZipArchive::CREATE) !== true) { // open file
die ("Could not open archive");//If the file does not open
}
$var = $_POST["pathUpload"];// Array of variables that are passed through the form
foreach ($var as $key_var) {// We process the array in a loop
$iterator = new RecursiveDirectoryIterator($key_var);//There is a recursive search of the file system directories
foreach ($iterator as $key => $value) {// We process an array of files
$path = pathinfo($value);//Check the path or revert the path to the file
if ($path['basename'] == '.' || $path['basename'] == '..') continue;//Check those files that you download if there are points in the files then download
$zip->addFile(realpath($key), $key);//Add the file to the server
}
$zip->close();//Close archive
if (file_exists($zip_name)) {
// Give the file to download
header('Content-type: application/zip', 'charset=utf-8');
header('Content-Disposition: attachment; filename="'.$zip_name.'"');
ob_end_flush();//Buffering since without it nothing will work
readfile($zip_name); //Read the file
unlink($zip_name);//Delete the variable
}
}
}
我很抱歉,但它是可能仍然是一个问题poche这是必要的我介入代码作为严格文件夹,并没有错误 – Vadim