SQL Server发送状态到电子邮件

Question

嘿大家都希望一切都好。我需要你的专业知识。

我有一个HTML的形式和它里面我有一个下拉选项中选择一个状态

<select name="State"> 
    <option value="0" selected="selected">Select a State</option> 
    <option value="AL">Alabama</option> 
    <option value="AK">Alaska</option> 
    <option value="AZ">Arizona</option> 
    <option value="AR">Arkansas</option> 
     etc..... 
</select> 

任何时间客户选择AA状态，并提交它去我的SQL Server数据库和表格获取与他们在html表单中选择的状态相关的IP地址。

+-----------+-------+---------------+ 
| stateip_id| state | user_ip  | 
+-----------+-------+---------------+ 
|  1 | AL | 67.100.244.74 | 
|  2 | AK | 68.20.131.135 | 
|  3 | AZ | 64.134.225.33 | 
+-----------+-------+---------------+ 

因此，举例来说，可以说，他们选择阿拉巴马（AL），当他们提交表单我想要的代码连接到PHP文件，然后显示相关的状态的IP地址，在此情况下（ AL）。我对这个感谢这个论坛的一些PHP代码和其他

<?php 
// visit http://php.net/pdo for more details 
// start error handling 

try 
{ 
$Server = "00.00.000.000,0000"; 
$User = "username"; 
$Pass = "password"; 
$DB = "dbname"; 

//connection to the database 
$dbhandle = mssql_connect($Server, $User, $Pass) 
    or die("Couldn't connect to SQL Server on $Server"); 

//select a database to work with 
$selected = mssql_select_db($DB, $dbhandle) 
    or die("Couldn't open database $DB"); 

$state = $_POST['State']; 

$query = "SELECT TOP 1 user_ip 
       FROM state_ip 
       WHERE state='$state' 
       ORDER BY newid()"; 

//execute the SQL query and return records 
$result = mssql_query($query); 

$numRows = mssql_num_rows($result); 
echo "<h1>" . $numRows . " Row" . ($numRows == 1 ? "" : "s") . " Returned </h1>"; 

//display the results 
while($row = mssql_fetch_array($result)); 

} 
catch (Exception $e) 
{ 
    echo "sorry, there was an error."; 
    mail("email@gmail.com", "database error", $e->getMessage(), "From: email@gmail.com"); 
} 

if(isset($_POST['email'])) { 

    // EDIT THE 2 LINES BELOW AS REQUIRED 
    $email_to = "email@gmail.com"; 
    $email_subject = "This is a test"; 


    function died($error) { 
     // your error code can go here 
     echo "We are very sorry, but there were error(s) found with the form you submitted. "; 
     echo "These errors appear below.<br /><br />"; 
     echo $error."<br /><br />"; 
     echo "Please go back and fix these errors.<br /><br />"; 
     die(); 
    } 

    // validation expected data exists 
    if(!isset($_POST['first_name']) || 
     !isset($_POST['last_name']) || 
     !isset($_POST['email']) || 
     !isset($_POST['what']) || 
     !isset($_POST['State']) || 
     !isset($_POST['comments'])) { 
     died('We are sorry, but there appears to be a problem with the form you submitted.');  
    } 

    $what = $_POST['what']; // required 
    $first_name = $_POST['first_name']; // required 
    $last_name = $_POST['last_name']; // required 
    $email_from = $_POST['email']; // required 
    $state = $_POST['State']; // not required 
    $comments = $_POST['comments']; // required 

    $error_message = ""; 
    $email_exp = '/^[A-Za-z0-9._%-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,4}$/'; 
    if(!preg_match($email_exp,$email_from)) { 
    $error_message .= 'The Email Address you entered does not appear to be valid.<br />'; 
    } 
    $string_exp = "/^[A-Za-z .'-]+$/"; 
    if(!preg_match($string_exp,$first_name)) { 
    $error_message .= 'The First Name you entered does not appear to be valid.<br />'; 
    } 
    if(!preg_match($string_exp,$last_name)) { 
    $error_message .= 'The Last Name you entered does not appear to be valid.<br />'; 
    } 
    if(strlen($comments) < 2) { 
    $error_message .= 'The Comments you entered do not appear to be valid.<br />'; 
    } 
    if(strlen($error_message) > 0) { 
    died($error_message); 
    } 
    $email_message = "Form details below.\n\n"; 

    function clean_string($string) { 
     $bad = array("content-type","bcc:","to:","cc:","href"); 
     return str_replace($bad,"",$string); 
    } 

    $email_message .= "First Name: ".clean_string($first_name)."\n"; 
    $email_message .= "Last Name: ".clean_string($last_name)."\n"; 
    $email_message .= "What: ".clean_string($what)."\n"; 
    $email_message .= "Email: ".clean_string($email_from)."\n"; 
    $email_message .= "State: ".clean_string($state)."\n"; 
    $email_message .= "Comments: ".clean_string($comments)."\n"; 
// create email headers 
$headers = 'From: '.$email_from."\r\n". 
'Reply-To: '.$email_from."\r\n" . 
'X-Mailer: PHP/' . phpversion(); 
if (!mail($email_to, $email_subject, $email_message, $headers)) 
{ 
    echo "failed to send message"; 
} 

?> 


<!-- include your own success html here --> 

Thank you for contacting us. We will be in touch with you very soon. 

<?php 
} 
?> 

这上面的代码的伟大工程，我收集了随机状态并与形式的信息的其余部分发送到我的邮箱。我遇到的问题是，在发送给我的邮件中，例如发送给我“AL或AZ或CA等”。它不会向我发送IP地址。我认为它与这行代码有关

$email_message .= "State: ".clean_string($state)."\n"; 

主要是$ state部分。我希望它选择user_ip部分，但不知道如何去做。我曾经试过，但它不工作

$email_message .= "State: ".clean_string('user_ip')."\n"; 

这是怎么显示在一封电子邮件中

First Name: afdf 
Last Name: sfgsdf 
What: hellow 
Email: sd@fd.com 
State: AL 
Comments: ali alabama2 

我想这是这个

First Name: afdf 
Last Name: sfgsdf 
What: hellow 
Email: sd@fd.com 
State: 123.456.1.21 
Comments: ali alabama2 

Answer 1

它做什么你”已经将它编码为：

$email_message .= "State: ".clean_string($state)."\n"; 

你填充变量$ result这里的IP地址：

$query = "SELECT TOP 1 user_ip 
       FROM state_ip 
       WHERE state='$state' 
       ORDER BY newid()"; 

//execute the SQL query and return records 
$result = mssql_query($query); 

所以，你真的需要$结果，而不是$状态：

$email_message .= "State: ".clean_string($result)."\n";