SQLite数据库列不存在

-1

我已经浏览了几个关于列不存在错误的问题，大多数都是间距问题或与模式有关的问题，这可以通过修复卸载并重新安装应用程序。我校对了我的声明，并尝试从我的手机中卸载应用程序，然后从android studio重新下载。似乎也没有解决我的问题。SQLite数据库列不存在

这里该行引发错误：

Cursor cursor = db.rawQuery("SELECT * FROM " + TABLE_NAME + " WHERE " + DATE_TO_REMIND + "='" + date + "'", null);

它的意图是把表中的每个元素（其列同行），有这是一个参数，我想要的日期（。我有方法（getWordsToReview）

我不断收到错误是这样的：

Caused by: android.database.sqlite.SQLiteException: no such column: Date_To_Remind (code 1): , while compiling: SELECT * FROM Vocabulary WHERE Date_To_Remind='2016/03/05'

该类的其余部分是这样的：

public class DBHelper extends SQLiteOpenHelper { 

    private static final int DATABASE_VERSION = 1; 
    private static final String DATABASE_NAME = "vocab.db"; 
    public static final String VOCAB_INPUT = "Input_Word"; 
    public static final String VOCAB_TRANSLATION = "Translation"; 
    public static final String DATE_TO_REMIND = "Date_To_Remind"; 
    public static final String TABLE_NAME = "Vocabulary"; 

    public DBHelper(Context context) { 
     super(context, DATABASE_NAME, null, DATABASE_VERSION); 
    } 

    @Override 
    public void onCreate(SQLiteDatabase db) { 
     String query = "CREATE TABLE " + TABLE_NAME + "(" 
       + VOCAB_INPUT + " TEXT " 
       + VOCAB_TRANSLATION + " TEXT " 
       + DATE_TO_REMIND + " TEXT" 
       + ");"; 
     db.execSQL(query); 
    } 

    @Override 
    public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) { 
     db.execSQL("DROP TABLE IF EXISTS " + TABLE_NAME); 
     onCreate(db); 
    } 

    public void addWord(Word word) { 
     ContentValues values = new ContentValues(); 
     values.put(VOCAB_INPUT, word.getWord()); 
     values.put(VOCAB_TRANSLATION, word.getTranslation()); 
     values.put(DATE_TO_REMIND, word.getDate()); 
     SQLiteDatabase db = getWritableDatabase(); 
     db.insert(TABLE_NAME, null, values); 
     db.close(); 
    } 

    public void deleteWord(Word word) { 
     SQLiteDatabase db = getWritableDatabase(); 
     db.execSQL("DELETE FROM " + TABLE_NAME + " WHERE " + VOCAB_INPUT + "=\"" + word.getWord() + "\""); 
    } 

    public List<Word> getWordsToReview(String date) { 
     List<Word> returnWords = new ArrayList<>(); 
     SQLiteDatabase db = getReadableDatabase(); 
     Cursor cursor = db.rawQuery("SELECT * FROM " + TABLE_NAME + " WHERE " + DATE_TO_REMIND + "='" + date + "'", null); 
     while (cursor.moveToNext()) { 
      String retrievedName = cursor.getString(cursor.getColumnIndex(VOCAB_INPUT)); 
      String retrievedTranslation = cursor.getString(cursor.getColumnIndex(VOCAB_TRANSLATION)); 
      String retrievedDate = cursor.getString(cursor.getColumnIndex(DATE_TO_REMIND)); 
      Word tempWord = new Word(retrievedName, retrievedTranslation, retrievedDate); 
      returnWords.add(tempWord); 
     } 
     cursor.close(); 
     return returnWords; 
    } 

    public boolean doesWordExist(Word word) { 
     SQLiteDatabase db = getReadableDatabase(); 
     Cursor cursor = db.rawQuery("SELECT * FROM " + TABLE_NAME + " WHERE " + VOCAB_INPUT + "=\"" + word.getWord() + "\"", null); 
     boolean exists = false; 
     while (cursor.moveToNext()) { 
      String retrievedName = cursor.getString(cursor.getColumnIndex(VOCAB_INPUT)); 
      if (retrievedName.equalsIgnoreCase(word.getWord())) { 
       exists = true; 
       break; 
      } 
     } 
     cursor.close(); 
     return exists; 
    } 
}

来源

2016-03-05 NuffsaidM8

不应该在'onCreate（）'中的每个'TEXT'后面加一个逗号来分隔列吗？ – PPartisan

另外请注意，您的日期格式不正确。它必须是'2016-03-05'。 –

@BobMalooga你为什么这么说？当我在另一个课程中格式化日期时，日期格式如下：2016/03/05 – NuffsaidM8

您在创建表中缺少一些逗号，所以表不会按照您的预期创建;

String query = "CREATE TABLE " + TABLE_NAME + "(" 
       + VOCAB_INPUT + " TEXT, "   // <-- added comma 
       + VOCAB_TRANSLATION + " TEXT, "  // <-- added comma 
       + DATE_TO_REMIND + " TEXT" 
       + ");";

来源

2016-03-05 18:25:23

这将是问题。我是一个doofus！我会尽快接受答案。 – NuffsaidM8

SQLite数据库列不存在

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