QWidget :: insertAction尝试在运行时插入空动作

所以，我试图在QT Creator中运行我的电子表格应用程序，它编译时没有错误，但是当我尝试运行该应用程序时，出现以下错误QWidget::insertAction Attempt to insert null action。问题是我不知道问题来自哪里......错误不会出现在QT Creator的错误部分，而是在运行程序时创建的小终端中。QWidget :: insertAction尝试在运行时插入空动作

我有一个createActions()函数，用于初始化标题中启动的所有动作，可能是从那里来的？

在头的私处的动作是这样的：

QAction *newAction; 
    QAction *openAction; 
    QAction *aboutQtAction; 

    QAction *closeAction; 
    QAction *exitAction; 
    QAction *selectAllAction; 
    QAction *showGridAction; 
    QAction *saveAction; 
    QAction *saveAsAction; 
    QAction *cutAction; 
    QAction *copyAction; 
    QAction *pasteAction; 
    QAction *deleteAction; 
    QAction *selectRowAction; 
    QAction *selectColumnAction; 
    QAction *findAction; 
    QAction *goToCellAction; 
    QAction *recalculateAction; 
    QAction *sortAction; 
    QAction *autoRecalcAction; 
    QAction *aboutAction;

这里的功能：

void MainWindow::createActions() 
{ 
    newAction = new QAction(tr("&New"), this); 
    newAction->setIcon(QIcon(":/images/avatar.jpeg")); 
    newAction->setShortcut(QKeySequence::New); 
    newAction->setStatusTip(tr("Create a new spreadsheet file")); 
    connect(newAction, SIGNAL(triggered()), this, SLOT(newFile())); 

    for (int i = 0; i < MaxRecentFiles; ++i) { 
    recentFileActions[i] = new QAction(this); 
    recentFileActions[i]->setVisible(false); 
    connect(recentFileActions[i], SIGNAL(triggered()),this, SLOT(openRecentFile())); 
    } 

    closeAction = new QAction(tr("&Close"), this); 
    closeAction->setShortcut(QKeySequence::Close); 
    closeAction->setStatusTip(tr("Close this window")); 
    connect(closeAction, SIGNAL(triggered()), this, SLOT(close())); 

    exitAction = new QAction(tr("E&xit"), this); 
    exitAction->setShortcut(tr("Ctrl+Q")); 
    exitAction->setStatusTip(tr("Exit the application")); 
    connect(exitAction, SIGNAL(triggered()), 
     qApp, SLOT(closeAllWindows())); 
    selectAllAction = new QAction(tr("&All"), this); 
    selectAllAction->setShortcut(QKeySequence::SelectAll); 
    selectAllAction->setStatusTip(tr("Select all the cells in the " 
            "spreadsheet")); 
    connect(selectAllAction, SIGNAL(triggered()), 
    spreadsheet, SLOT(selectAll())); 

    showGridAction = new QAction(tr("&Show Grid"), this); 
    showGridAction->setCheckable(true); 
    showGridAction->setChecked(spreadsheet->showGrid()); 
    showGridAction->setStatusTip(tr("Show or hide the spreadsheet's " 
            "grid")); 
    connect(showGridAction, SIGNAL(toggled(bool)), 
    spreadsheet, SLOT(setShowGrid(bool))); 

    aboutQtAction = new QAction(tr("About &Qt"), this); 
    aboutQtAction->setStatusTip(tr("Show the Qt library's About box")); 
    connect(aboutQtAction, SIGNAL(triggered()), qApp, SLOT(aboutQt())); 
    }

这些行动，在被创建后，被添加到菜单中createMenus()功能：

void MainWindow::createMenus(){ 
fileMenu = menuBar()->addMenu(tr("&File")); 
fileMenu->addAction(newAction); 
fileMenu->addAction(openAction); 
fileMenu->addAction(saveAction); 
fileMenu->addAction(saveAsAction); 

separatorAction = fileMenu->addSeparator(); 
for (int i = 0; i < MaxRecentFiles; ++i) 
    fileMenu->addAction(recentFileActions[i]); 

fileMenu->addSeparator(); 
fileMenu->addAction(exitAction); 
...

有人有任何想法，这个错误来了f只读存储器？

谢谢！阿克塞尔

来源

2012-03-10 Axel

在createActions()，你似乎没有被初始化openAction，saveAction，或saveAsAction - 你再插入到您的菜单。我猜这就是问题所在，除非你没有包含初始化这些特定操作的代码。

来源

2012-03-10 22:02:36 tmpearce

我的不好，这个动作是在头文件中初始化的，不好添加相关部分。 – Axel 2012-03-10 22:06:00

@Axel你刚刚添加的东西 - 指针在头文件中被定义*你在哪里做'saveAction = new QAction（）'？那是他们得到*创建的时候* – tmpearce 2012-03-10 22:11:47

哦，刚刚意识到某些动作从未实现过，这很有趣，因为我强硬的那些错误会在编译为错误时弹出。所以我有点惊讶他们没有在错误输出面板中显示错误QTCreator oo – Axel 2012-03-10 22:21:17

QWidget :: insertAction尝试在运行时插入空动作

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