如何解析ISO8601日期

Question

我得到关于这种格式的日期字符串：

2011-12-29T09:09:06-0500 

我如何转换到这个约会对象？

Answer 1

NSString *date = [[NSDate date] description]; 

[NSDateFormatter setDefaultFormatterBehavior:NSDateFormatterBehavior10_4]; 
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init]; 
[dateFormatter setDateFormat:@"yyyy'-'MM'-'dd'T'HH':'mm':'ss'Z'"]; 

NSDate *dateFromString = [[NSDate alloc] init]; 
dateFromString = [dateFormatter dateFromString:<NSString containing date>]; 

Answer 2

尝试这种解决方案

NSString *dateString = @"2011-12-29T09:09:06-0500"; 
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init]; 
[dateFormatter setDateFormat:@"yyyy-MM-dd'T'HH:mm:ssZ"]; 

NSDate *dateFromString = [dateFormatter dateFromString:dateString];  
[dateFormatter release]; 
NSLog(@" dateFromString %@",dateFromString);