在Android中上传视频

Question

我想在Android中的特定服务器上上传视频。

可以吗？

我该如何做到这一点？

谢谢。

Answer 1

前段时间有同样的问题。这是一个代码。

public static int upLoad2Server(String sourceFileUri) 
{ 
String upLoadServerUri = "your remote server link"; 
// String [] string = sourceFileUri; 
String fileName = sourceFileUri; 

HttpURLConnection conn = null; 
DataOutputStream dos = null; 
DataInputStream inStream = null; 
String lineEnd = "\r\n"; 
String twoHyphens = "--"; 
String boundary = "*****"; 
int bytesRead, bytesAvailable, bufferSize; 
    byte[] buffer; 
int maxBufferSize = 1 * 1024 * 1024; 
String responseFromServer = ""; 

File sourceFile = new File(sourceFileUri); 
if (!sourceFile.isFile()) { 
Log.e("Huzza", "Source File Does not exist"); 
return 0; 
    } 
try { // open a URL connection to the Servlet 
FileInputStream fileInputStream = new FileInputStream(sourceFile); 
URL url = new URL(upLoadServerUri); 
conn = (HttpURLConnection) url.openConnection(); // Open a HTTP connection to the URL 
conn.setDoInput(true); // Allow Inputs 
conn.setDoOutput(true); // Allow Outputs 
conn.setUseCaches(false); // Don't use a Cached Copy 
conn.setRequestMethod("POST"); 
conn.setRequestProperty("Connection", "Keep-Alive"); 
conn.setRequestProperty("ENCTYPE", "multipart/form-data"); 
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary); 
conn.setRequestProperty("uploaded_file", fileName); 
dos = new DataOutputStream(conn.getOutputStream()); 

dos.writeBytes(twoHyphens + boundary + lineEnd); 
dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\""+ fileName + "\"" + lineEnd); 
dos.writeBytes(lineEnd); 

bytesAvailable = fileInputStream.available(); // create a buffer of maximum size 
Log.i("Huzza", "Initial .available : " + bytesAvailable); 

bufferSize = Math.min(bytesAvailable, maxBufferSize); 
buffer = new byte[bufferSize]; 

// read file and write it into form... 
bytesRead = fileInputStream.read(buffer, 0, bufferSize); 

while (bytesRead > 0) { 
    dos.write(buffer, 0, bufferSize); 
    bytesAvailable = fileInputStream.available(); 
    bufferSize = Math.min(bytesAvailable, maxBufferSize); 
bytesRead = fileInputStream.read(buffer, 0, bufferSize); 
    } 

// send multipart form data necesssary after file data... 
dos.writeBytes(lineEnd); 
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd); 

// Responses from the server (code and message) 
serverResponseCode = conn.getResponseCode(); 
String serverResponseMessage = conn.getResponseMessage(); 

Log.i("Upload file to server", "HTTP Response is : " + serverResponseMessage + ": " + serverResponseCode); 
// close streams 
Log.i("Upload file to server", fileName + " File is written"); 
fileInputStream.close(); 
dos.flush(); 
dos.close(); 
} catch (MalformedURLException ex) { 
ex.printStackTrace(); 
Log.e("Upload file to server", "error: " + ex.getMessage(), ex); 
} catch (Exception e) { 
e.printStackTrace(); 
} 
//this block will give the response of upload link 
    try { 
    BufferedReader rd = new BufferedReader(new InputStreamReader(conn 
    .getInputStream())); 
    String line; 
    while ((line = rd.readLine()) != null) { 
    Log.i("Huzza", "RES Message: " + line); 
    } 
    rd.close(); 
} catch (IOException ioex) { 
    Log.e("Huzza", "error: " + ioex.getMessage(), ioex); 
} 
return serverResponseCode; // like 200 (Ok) 

} // end upLoad2Server