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我正在让我的菜单项显示在ListView页面上,但是当我单击链接时,没有任何数据正确显示。Django我的模型没有从文件传输到文件
这里是我的菜单carousel.html
{% for item in object_list %}
<li>
<div class="impx-menu-page-item">
<div class="impx-menu-page-content">
<h4><a href="/menu/{{ item.id }}">{{ item.title }}</a></h4>
<div class="impx-menu-page-price">
<h5>${{ item.price }}</h5>
</div>
<p>{{ item.description }}</p>
</div>
</div>
</li>
{% endfor %}
而且这样的作品,现在这里是破碎的一部分,当我到/菜单/ 1 /菜单/“无论数量”
<div class="container">
<div class="row">
<h3><a href="/menu/{{ item.id }}"></a>{{ item.title }}</h3>
</div>
<div class="row">
<div class = "col-sm-12 col-md-4">
<img src="{{ item.image.url }}" height="300px" width="300px" class = "img img-responsive thumbnail"/>
</div>
<div class = "col-sm-12 col-md-4">
<h6>Price: ${{ item.price }}</h6>
<h6>Materials: {{ item.description }}</h6>
</div>
<div class = "col-sm-12 col-md-4">
<p>{{ item.description|safe|linebreaks }}</p><br /><br />
<hr />
<h5></h5>
</div>
<br><br>
</div>
</div>
这是在我的浏览器
<div class="container">
<div class="row">
<h3><a href="/menu/"></a></h3>
</div>
<div class="row">
<div class = "col-sm-12 col-md-4">
<img src="" height="300px" width="300px" class = "img img-responsive thumbnail"/>
</div>
<div class = "col-sm-12 col-md-4">
<h6>Price: $</h6>
<h6>Materials: </h6>
</div>
<div class = "col-sm-12 col-md-4">
<p><p></p></p><br /><br />
<hr />
<h5></h5>
</div>
<br><br>
</div>
</div>
这里显示是我的urls.py
from django.conf.urls import url, include
from django.views.generic import ListView, DetailView
from django.contrib import admin
from . import views
from home.models import Menu
urlpatterns = [
url(r'^$', views.home, name="home"),
url(r'^menu/$', ListView.as_view(
queryset=Menu.objects.all().order_by("-title")[:25],
template_name="menu-carousel.html")),
url(r'^menu/(?P<pk>\d+)/$', DetailView.as_view(
model = Menu,
template_name="menu-item.html")),
]
,这里是我的models.py
from django.db import models
from django.conf import settings
class Menu(models.Model):
title = models.CharField(max_length = 140)
price = models.IntegerField()
description = models.TextField()
image = models.ImageField(upload_to = 'media/')
menu = models.CharField(max_length = 10)
def __str__(self):
return self.title
谢谢!这解决了它!现在我只需要弄清楚如何让我的图像正确显示! – user3481670