2010-09-21 127 views
0

我是OOP的新手,我试图掌握它。我想要做的是返回表中的所有数据。现在只有2行,但我不知道如何将所有数据放入数组,然后将其返回到$ results变量。试图从一个类传递数组到另一个类

请帮忙。

<?php 
include('dates.php'); 

$events = new dates(); 
echo $events->getNumberEvents(); <-----returns the number of rows in the table (Works as expected) 

$results = $events->getRows(); <------Doesn't work. 

?> 

日期类

<?php 
/******************************************** 
* Class to connect and get dates from a database 
*********************************************/ 
require 'phpDatabaseClass.php'; 

class dates{ 

    private $db; 
    private $arr2 = array(); 

    /**************************** 
    * Constructor which creates the $db variable 
    ****************************/ 
    function __construct() 
    { 
     $this->db = new phpDatabaseClass(); 
    } 

    /**************************** 
    * Function which calls the database class and returns the number of rows 
    ****************************/ 
    public function getNumberEvents() 
    { 
     $sql = "select count(*) from events";   
     return $this->db->queryNumber($sql); 
    } 

    /**************************** 
    * Function which calls the database class and returns the actual rows 
    ****************************/ 
    public function getRows() 
    { 
     $sql = "select * from events"; 

     $this->arr2 = $this->db->queryString($sql); 

     foreach($this->arr2 as $key=>$val) 
     { 
      //$this->arr2 = $val; 
      //echo $val;  
     } 

    } 
} 
?> 

phpDatabaseClass

<?php 
/******************************************** 
* Class to connect and query a mysql database 
*********************************************/ 
require 'config.php'; 

class phpDatabaseClass { 

    private $db; 
    private $arr = array(); 

    /**************************** 
    * Constructor function which makes the connection to the database 
    ****************************/ 
    public function __construct() 
    { 
     try 
     { 
      $this->db = new PDO("mysql:host=".DB_HOST.";dbname=".DB_NAME, DB_USERNAME, DB_PASSWORD); 
     } 
     catch(PDOexception $e) 
     { 
      echo 'Can\'t connect to database. Please contact the site administrator'; 
     } 
    } 

    /**************************** 
    * Function which returns the number of rows 
    ****************************/ 
    public function queryNumber($sql) 
    {       
     $stmt = $this->db->prepare($sql); 
     $stmt->execute(); 
     $resultsCount = $stmt->fetchColumn(); 

     return $resultsCount; 
    } 


    /**************************** 
    * Function which returns the data in the rows 
    ****************************/ 
    public function queryString($sql) 
    {       
     $stmt = $this->db->prepare($sql); 

     $stmt->execute(); 

     $results = $stmt->fetch(PDO::FETCH_ASSOC); 

     foreach($results as $key=>$val) 
     { 
      $this->arr = $val; 
      //echo $this->arr; 
     } 

     return array($this->arr); 
    } 
} 
?> 

回答

2
public function getRows() 
{ 
    $sql = "select * from events"; 

    $this->arr2 = $this->db->queryString($sql); 
    $return = array(); 
    foreach($this->arr2 as $key=>$val) 
    { 
     $return[$key] = $val; 
    } 
    return $return; 
} 

,如果你想在这个阶段做任何事情,就是。为了简单地返回,你可以这样做:

return $this->db->queryString($sql); 

为了呼应信息:

foreach($results as $result) 
{ 

    echo $result->fieldname; 

} 

为了呼应的一切需要:

foreach($results as $result) 
{ 
    foreach($result as $key => $value) 
    { 
     echo $key.': '.$value; 
    } 

} 

原因访问作为一个对象,而不是一个数组是mysqli将行作为对象返回。

+0

如果我只是返回$ this-> db-> queryString($ sql),那么我如何输出所有的值?如果我在我的原始调用中这样做:$ results = $ events-> getRows(); \t \t foreach($ result as $ key => $ val){\t \t \t echo $ val; \t}它只打印出第一行数据的最后一列。 – Catfish 2010-09-21 19:49:42

+0

编辑原始答案。 – Gazler 2010-09-21 19:53:04

+0

但是如果我不想在getRows函数中回显,我只想将结果一直返回到原始调用? – Catfish 2010-09-21 19:55:05

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