6
服务器收到来自两个客户端的请求 - Raspberry Pi和Android应用程序,都使用HttpURLConnection发送请求。我需要与theese请求传递参数,例如:如何从HttpServletRequest(Tomcat 9.0)获取查询参数?
http://192.168.0.10:8080/MyProject/MyServer/rpi/checktask?rpi="rpi"
做它:
String requestUrl = "http://192.168.0.10:8080/MyProject/MyServer/rpi";
String query = String.format("/checktask?rpi=%s",
URLEncoder.encode("rpi", "UTF-8"));
URL url = new URL(requestUrl + query);
conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
conn.setDoInput(true);
conn.setRequestProperty("Accept-Charset", "UTF-8");
conn.connect();
的servlet有注释:
@WebServlet(name = "MyServer", urlPatterns = { "/MyServer/rpi/*", "/MyServer/app/*"})
但是当Servlet的获取请求,如上以下情况:
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String path = request.getRequestURI(); // /MyProject/MyServer/rpi/*
String query = request.getQueryString(); // null
String context = request.getContextPath(); // /MyProject
String servlet = request.getServletPath(); // /MyServer/rpi
String info = request.getPathInfo(); // /*
}
虽然根据这些问题的答案: How to use @WebServlet to accept arguments (in a RESTFul way)? 和 How come request.getPathInfo() in service method returns null?
它应该是这样的:
String path = request.getRequestURI(); // /MyProject/MyServer/rpi//checktask?rpi="rpi"
String query = request.getQueryString(); // rpi="rpi"
String context = request.getContextPath(); // /MyProject
String servlet = request.getServletPath(); // /MyServer/rpi
String info = request.getPathInfo(); // /checktask?rpi="rpi"
我在做什么错?
如果您尝试手动点击网址(例如,使用浏览器)是否有效? – Taylor
它不适用于浏览器和应用程序。 – Katrikken
我的回答是垃圾,对不起。我现在有点困惑,并且正在阅读Servlet规范,这个主题的百分之一时间.... :-( – gsl