为什么此验证代码无法按预期工作？

Question

我有一个表单和m的行为是相同的页面。 我想：

1. 在成功提交表单显示一个感谢的消息旁边，在那里检测到错误
2. 上述所有必须在同一页面中显示的字段
3. 显示错误消息。

我的代码是：

<?php 
    $errors = array(); 
    if (isset($_POST["Ask_the_Question"])) { 
     $guest_name = $_POST["guest_name"]; 
     $title = $_POST["faq_title"]; 
     $description = $_POST["faq_desc"]; 
     $title = $_POST["faq_title"]; 

     /* validation */ 
     if (empty($guest_name)) { 
      $errors['guest_name'] = "Please type your name!"; 
     } 

     if(!empty($errors)){ echo '<h1 style="color: #ff0000;">Errors!</h1><h6 style="color: #ff0000;">Please check the fields which have errors below. Error hints are in Red.</h6>';} 

     if(empty($errors)){  
      echo 'Thanks, We have received your feed back'; 
     } 
    } 

    else { 
?> 
      <form action="index.php" method="post" class="booking_reference"> 
       <input type="text" name="guest_name" placeholder="Your Name" value="<?PHP if(!empty($errors)) { echo $guest_name;} ?>" /> 
       <?php if(isset($errors['guest_name'])) { echo '<span style="color: red">'.$errors['guest_name'].'</span>'; } ?> 
       <input type="email" name="guest_email" placeholder="Your email" pattern="[a-z0-9._%+-]+@[a-z0-9.-]+\.[a-z]{2,4}$" required /> 
       <input type="text" name="faq_title" placeholder="FAQ Title"/> 
       <input type="text" name="faq_desc" placeholder="FAQ Description"/> 
       <input type="submit" name="Ask_the_Question" value="Ask the Question" /> 
      </form> 
<?php 
     } 
?> 

我已经限制了验证，并只显示了在这个问题上的第一部分。

当我提交此表，如果没有任何错误，我收到消息谢谢，我们已经收到您的反馈 这是罚款和按预期工作。

当出现错误/字段客人姓名为空我在表单提交过程中收到消息错误！ 请检查下面有错误的字段。错误提示以红色显示。 这也很好。

但我的窗体正好消失当我得到上面的消息。为什么？ 也想显示请输入您的姓名！旁边的领域。

Answer 1

尝试下面的代码。我已经删除了其他部分，并设置了真/假标志来检查是否有效。

<?php 
    $errors = array(); 
    if (isset($_POST["Ask_the_Question"])) { 
     $guest_name = $_POST["guest_name"]; 
     $title = $_POST["faq_title"]; 
     $description = $_POST["faq_desc"]; 
     $title = $_POST["faq_title"]; 

     /* validation */ 
     $chkValidate = "true"; 
     if (empty($guest_name)) { 
      $errors['guest_name'] = "Please type your name!"; 
      $chkValidate = "false"; 
     } 

     if(!empty($errors)){ echo '<h1 style="color: #ff0000;">Errors!</h1><h6 style="color: #ff0000;">Please check the fields which have errors below. Error hints are in Red.</h6>'; 
      $chkValidate = "false"; 
     } 

     if($chkValidate == "true"){  
      echo 'Thanks, We have received your feed back'; 
     } 
    } 
    ?> 
      <form action="index.php" method="post" class="booking_reference"> 
       <input type="text" name="guest_name" placeholder="Your Name" value="<?php if(!empty($errors) && $chkValidate != "false") { echo $guest_name;} ?>" /> 
       <?php if(isset($errors['guest_name'])) { echo '<span style="color: red">'.$errors['guest_name'].'</span>'; } ?> 
       <input type="email" name="guest_email" placeholder="Your email" pattern="[a-z0-9._%+-]+@[a-z0-9.-]+\.[a-z]{2,4}$" required /> 
       <input type="text" name="faq_title" placeholder="FAQ Title"/> 
       <input type="text" name="faq_desc" placeholder="FAQ Description"/> 
       <input type="submit" name="Ask_the_Question" value="Ask the Question" /> 
      </form> 
<?php 

?> 

Answer 2

只是删除else条件的原因其实你的形式也不会显示如果$_POST["Ask_the_Question"]设置

<?php 
    $errors = array(); 
    if (isset($_POST["Ask_the_Question"])) { 
     $guest_name = $_POST["guest_name"]; 
     $title = $_POST["faq_title"]; 
     $description = $_POST["faq_desc"]; 
     $title = $_POST["faq_title"]; 

     /* validation */ 
     if (empty($guest_name)) { 
      $errors['guest_name'] = "Please type your name!"; 
     } 

     if(!empty($errors)){ echo '<h1 style="color: #ff0000;">Errors!</h1><h6 style="color: #ff0000;">Please check the fields which have errors below. Error hints are in Red.</h6>';} 

     if(empty($errors)){  
      echo 'Thanks, We have received your feed back'; 
     } 
    } 
      <form action="index.php" method="post" class="booking_reference"> 
       <input type="text" name="guest_name" placeholder="Your Name" value="<?PHP if(!empty($errors)) { echo $guest_name;} ?>" /> 
       <?php if(isset($errors['guest_name'])) { echo '<span style="color: red">'.$errors['guest_name'].'</span>'; } ?> 
       <input type="email" name="guest_email" placeholder="Your email" pattern="[a-z0-9._%+-]+@[a-z0-9.-]+\.[a-z]{2,4}$" required /> 
       <input type="text" name="faq_title" placeholder="FAQ Title"/> 
       <input type="text" name="faq_desc" placeholder="FAQ Description"/> 
       <input type="submit" name="Ask_the_Question" value="Ask the Question" /> 
      </form> 

Answer 3

的原因是在这里：

<?php 
if (isset($_POST["Ask_the_Question"])) { 
     $guest_name = $_POST["guest_name"]; 
     $title = $_POST["faq_title"]; 
     $description = $_POST["faq_desc"]; 
     $title = $_POST["faq_title"]; 

     /* validation */ 
     if (empty($guest_name)) { 
      $errors['guest_name'] = "Please type your name!"; 
     } 

     if(!empty($errors)){ echo '<h1 style="color: #ff0000;">Errors!</h1><h6 style="color: #ff0000;">Please check the fields which have errors below. Error hints are in Red.</h6>';} 

     if(empty($errors)){  
      echo 'Thanks, We have received your feed back'; 
     } 
    } else { 
     // your form code will never be called if $_POST['Ask_the_Question'] is set 

做你想实现你可能想什么代之以做这样的事情：

<?php 
    $errors = array(); 
    if (isset($_POST["Ask_the_Question"])) { 
     $guest_name = $_POST["guest_name"]; 
     $title = $_POST["faq_title"]; 
     $description = $_POST["faq_desc"]; 
     $title = $_POST["faq_title"]; 

     /* validation */ 
     if (empty($guest_name)) { 
      $errors['guest_name'] = "Please type your name!"; 
     } 

     if(!empty($errors)){ echo '<h1 style="color: #ff0000;">Errors!</h1><h6 style="color: #ff0000;">Please check the fields which have errors below. Error hints are in Red.</h6>';} 
    } 

    if(empty($errors)){  
      echo 'Thanks, We have received your feed back'; 
     } else { ?> 
      <form action="index.php" method="post" class="booking_reference"> 
       <input type="text" name="guest_name" placeholder="Your Name" value="<?PHP if(!empty($errors)) { echo $guest_name;} ?>" /> 
       <?php if(isset($errors['guest_name'])) { echo '<span style="color: red">'.$errors['guest_name'].'</span>'; } ?> 
       <input type="email" name="guest_email" placeholder="Your email" pattern="[a-z0-9._%+-]+@[a-z0-9.-]+\.[a-z]{2,4}$" required /> 
       <input type="text" name="faq_title" placeholder="FAQ Title"/> 
       <input type="text" name="faq_desc" placeholder="FAQ Description"/> 
       <input type="submit" name="Ask_the_Question" value="Ask the Question" /> 
      </form> 
      <?php 

     } 
    } 

?> 

Answer 4

其他答案很好，但只是为了澄清会发生什么。

但是当我得到上面的消息时，我的表单就消失了。为什么？

你的形式消失了，因为如果你通过第一如果你不能让你的其他。

if (isset($_POST["Ask_the_Question"])) { 
    ... 
} else { 
    xxx; 
} 

，如果你想看到你的表格，你必须把它放在某个地方，这可以显示像elseif（有更多的限制），或IFS内部或外部的意思。

if (isset($_POST["Ask_the_Question"]) && empty($errors)) { 
    ... 
} elseif (isset($_POST["Ask_the_Question"]) && !empty($errors)) { 
    ... 
} else { 
    ... 
} 

另外我想表明，请输入您的姓名！在领域旁边。

要显示所有错误，您可以使用例如。在任何你想展示给他们的地方。

foreach ($errors as &$error) { 
    echo "Error: $error<br />\n"; 
} 

顺便说一句empty(); function。