我遇到了一个我正在创建的Android应用程序的问题。我有两个按钮和二者引起的通知按压之后,但在这里是问题进来,两者具有不变ID(1和2)如何在通知管理器(Android)上创建动态ID?
manager.notify(1, notification);
这意味着notification1,总是出现在首先在状态栏中。当您先按通知2时,它没有任何区别,它始终是通知1,然后是通知2。现在我需要知道如何使动态ID?
谁能告诉我一个解决方案,我可以如何避免不变的顺序?
这里的完整代码:
public void sendNotification(View view) {
switch(view.getId()){
case R.id.button1:
Notification1();
break;
case R.id.button2:
Notification2();
break;
}
}
private void Notification1() {
NotificationCompat.Builder builder = new NotificationCompat.Builder(this);
builder.setAutoCancel(true);
builder.setContentTitle("BasicNotification");
builder.setContentText("Test");
builder.setSmallIcon(R.drawable.icon1);
Notification notification = builder.build();
NotificationManager manager = (NotificationManager) this.getSystemService(NOTIFICATION_SERVICE);
manager.notify(1, notification);
}
private void Notification2() {
NotificationCompat.Builder builder = new NotificationCompat.Builder(this);
builder.setAutoCancel(true);
builder.setContentTitle("BasicNotification");
builder.setContentText("Test");
builder.setSmallIcon(R.drawable.icon2);
Notification notification = builder.build();
NotificationManager manager = (NotificationManager) this.getSystemService(NOTIFICATION_SERVICE);
manager.notify(2, notification);
}
感谢您的快速anwser!但我必须去哪里但这呢?对不起,但我真的noobie :( – DudeEffects 2014-09-03 19:39:47
.......见编辑 – r2DoesInc 2014-09-03 19:40:31
感谢男人!!! omg你是最好的:D 我在德国论坛寻求帮助,但它需要几天的时间,然后它没有工作,现在我在一个英语论坛,我2min后得到一个简短而称职的awnser:D再次感谢你从几个小时的谷歌救济我^^ – DudeEffects 2014-09-03 19:50:34