Php不会在数据库中创建用户

Question

我编写了一个代码，可以防止sql注入，但现在甚至不会创建用户。下面是我的代码：

<?php 
$user = $_GET['username']; 
$pass = $_GET['password']; 

$servername = "localhost"; 
$username = "root"; 
$password = ""; 
$dbname = "test123"; 

$conn = new mysqli($servername, $username, $password, $dbname); 
function selectInfo($user, $pass){ 
    global $conn; 
    $stmt = $conn->prepare("INSERT INTO users (username, password) VALUES (?, ?)"); 
    $stmt->bind_param("ss", $user, $pass); 
    $stmt->execute(); 
    $stmt->close(); 
    } 
?> 

执行时，我没有得到任何错误，但它并没有创造我需要的用户。 对不起，这些代码可能不正确。我在这个新的。

Answer 1

的真正原因是你是不是调用该函数

做这一点

<?php 
$user = $_GET['username']; 
$pass = $_GET['password']; 

$servername = "localhost"; 
$username = "root"; 
$password = ""; 
$dbname = "test123"; 

$conn = new mysqli($servername, $username, $password, $dbname); 
function selectInfo($user, $pass){ 
    global $conn; 
    $stmt = $conn->prepare("INSERT INTO users (username, password) VALUES (?, ?)"); 
    $stmt->bind_param("ss", $user, $pass); 
    $stmt->execute(); 
    $stmt->close(); 
    } 
selectInfo($user, $pass); 
?> 

或

<?php 
$user = $_GET['username']; 
$pass = $_GET['password']; 

$servername = "localhost"; 
$username = "root"; 
$password = ""; 
$dbname = "test123"; 

$conn = new mysqli($servername, $username, $password, $dbname); 

    $stmt = $conn->prepare("INSERT INTO users (username, password) VALUES (?, ?)"); 
    $stmt->bind_param("ss", $user, $pass); 
    $stmt->execute(); 
    $stmt->close(); 


?>