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即时为网站做一个快速更新,但xslt不是我的东西,它似乎与代码我看代码生成的代码失败 - 已包括两个以下:xml xsl template with html/js内部失败
当前代码:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp " "> ]>
<xsl:stylesheet
version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxml="urn:schemas-microsoft-com:xslt"
xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets" xmlns:tagsLib="urn:tagsLib"
exclude-result-prefixes="msxml umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings Exslt.ExsltSets tagsLib ">
<xsl:output method="xml" omit-xml-declaration="yes"/>
<xsl:param name="currentPage"/>
<xsl:template match="/">
<xsl:if test="string-length($currentPage/mp4videoLinkId) > 0">
<xsl:variable name="videoID" select="$currentPage/mp4videoLinkId" />
<xsl:variable name="srtID" select="$currentPage/mp4videoSRTId" />
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script src="flowplayer-3.2.6.min.js"></script>
<script src="flowplayer.ipad-3.2.2.min.js"></script>
<!-- player container-->
<a href="{$videoID}" style="display:block;width:473px;height:310px;" id="ipad"></a>
<script type="text/javascript">
$f("ipad", "flowplayer-3.2.7.swf",{
clip: {
autoPlay: false,
url: '{$videoID}',
// this is the Timed Text file with captions info
captionUrl: '{$srtID}'
},
plugins: {
captions: {
url: 'flowplayer.captions-3.2.3.swf',
// pointer to a content plugin (see below)
captionTarget: 'content'
},
// configure a content plugin to look good for our purpose
content: {
url:'flowplayer.content-3.2.0.swf',
bottom: 25,
width: '80%',
height:40,
backgroundColor: 'transparent',
backgroundGradient: 'none',
borderRadius: 4,
border: 0,
textDecoration: 'outline',
style: {
body: {
fontSize: 14,
fontFamily: 'Arial',
textAlign: 'center',
color: '#ffffff'
}
}
}
}
}).ipad();
</script>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
产生源: (你可以看到它打破了代码,而不是关闭,然后显示{$标签})我失去了什么?
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js" /><script src="flowplayer-3.2.6.min.js" /><script src="flowplayer.ipad-3.2.2.min.js" /><a href="mp4/assist-mi-car-parking.mp4" style="display:block;width:473px;height:310px;" id="ipad" /><script type="text/javascript">
$f("ipad", "flowplayer-3.2.7.swf",{
clip: {
autoPlay: false,
url: '{$videoID}',
// this is the Timed Text file with captions info
captionUrl: '{$srtID}'
},
plugins: {
captions: {
url: 'flowplayer.captions-3.2.3.swf',
// pointer to a content plugin (see below)
captionTarget: 'content'
},
// configure a content plugin to look good for our purpose
content: {
url:'flowplayer.content-3.2.0.swf',
bottom: 25,
width: '80%',
height:40,
backgroundColor: 'transparent',
backgroundGradient: 'none',
borderRadius: 4,
border: 0,
textDecoration: 'outline',
style: {
body: {
fontSize: 14,
fontFamily: 'Arial',
textAlign: 'center',
color: '#ffffff'
}
}
}
}
}).ipad();
</script>
很大,那现在显示的数据!然而,它仍然只包括jquery,没有看到萤火虫之后,在源代码中,它不关闭,我认为这可以防止休息显示..... – 2012-02-27 17:10:27
@JamesBrandon:您的XSLT转换可能有其他错误 - 你需要展示一个完整的(尽可能小的以便重现问题)XML文档,一个完整的(尽可能小但重现问题)XSLT转换,你得到的完整结果,你想要的完整结果*获得以及该转换必须实施的任何规则。至于这个问题,已经完全回答了。请为其他问题提出一个新问题,并提供所有必要的信息来重现这个新问题。 – 2012-02-27 17:16:06