SQL Server的时间间隔，以多行

我有一个的startDateTime和EndDateTime这个纪录，我想要的结果是在排15分钟的时间间隔：SQL Server的时间间隔，以多行

的样本数据：

FName | StartDateTime | EndDateTime :----- | -----------: | :--------------: Juan | 08/01/2017 1:00| 08/01/2017 8:00

结果：

FName | Interval :----- | -----------: Juan | 08/01/2017 1:00 Juan | 08/01/2017 1:15 Juan | 08/01/2017 1:30 Juan | 08/01/2017 1:45 Juan | 08/01/2017 2:00

，直到达到其EndDateTime，我怎么能在SQL实现这一目标。我在想使用循环语句或cte。

来源

2017-08-04 Mhundie

如果你是开放的TVF（表值函数）

我会经常使用这个UDF来创建动态的日期/时间范围。它比递归CTE和参数驱动更快。

的参数是日期1，日期2，日期部分，和增量

例

Declare @YourTable Table ([FName] varchar(50),[StartDateTime] datetime,[EndDateTime] datetime) 
Insert Into @YourTable Values 
('Juan','08/01/2017 1:00','08/01/2017 8:00') 

Select A.FName 
     ,B.* 
From @YourTable A 
Cross Apply [dbo].[udf-Range-Date](A.StartDateTime,A.EndDateTime,'MI',15) B

FName RetSeq RetVal 
Juan 1  2017-08-01 01:00:00.000 
Juan 2  2017-08-01 01:15:00.000 
Juan 3  2017-08-01 01:30:00.000 
Juan 4  2017-08-01 01:45:00.000 
Juan 5  2017-08-01 02:00:00.000 
... 
Juan 29  2017-08-01 08:00:00.000

的UDF如果有意

CREATE FUNCTION [dbo].[udf-Range-Date] (@R1 datetime,@R2 datetime,@Part varchar(10),@Incr int) 
Returns Table 
Return (
    with cte0(M) As (Select 1+Case @Part When 'YY' then DateDiff(YY,@R1,@R2)/@Incr When 'QQ' then DateDiff(QQ,@R1,@R2)/@Incr When 'MM' then DateDiff(MM,@R1,@R2)/@Incr When 'WK' then DateDiff(WK,@R1,@R2)/@Incr When 'DD' then DateDiff(DD,@R1,@R2)/@Incr When 'HH' then DateDiff(HH,@R1,@R2)/@Incr When 'MI' then DateDiff(MI,@R1,@R2)/@Incr When 'SS' then DateDiff(SS,@R1,@R2)/@Incr End), 
     cte1(N) As (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)), 
     cte2(N) As (Select Top (Select M from cte0) Row_Number() over (Order By (Select NULL)) From cte1 a, cte1 b, cte1 c, cte1 d, cte1 e, cte1 f, cte1 g, cte1 h), 
     cte3(N,D) As (Select 0,@R1 Union All Select N,Case @Part When 'YY' then DateAdd(YY, N*@Incr, @R1) When 'QQ' then DateAdd(QQ, N*@Incr, @R1) When 'MM' then DateAdd(MM, N*@Incr, @R1) When 'WK' then DateAdd(WK, N*@Incr, @R1) When 'DD' then DateAdd(DD, N*@Incr, @R1) When 'HH' then DateAdd(HH, N*@Incr, @R1) When 'MI' then DateAdd(MI, N*@Incr, @R1) When 'SS' then DateAdd(SS, N*@Incr, @R1) End From cte2) 

    Select RetSeq = N+1 
      ,RetVal = D 
    From cte3,cte0 
    Where D<[email protected] 
) 
/* 
Max 100 million observations -- Date Parts YY QQ MM WK DD HH MI SS 
Syntax: 
Select * from [dbo].[udf-Range-Date]('2016-10-01','2020-10-01','YY',1) 
Select * from [dbo].[udf-Range-Date]('2016-01-01','2017-01-01','MM',1) 
*/

来源

2017-08-04 11:34:06

你可以使用一个recursive query这样

DECLARE @SampleData AS TABLE 
(
    FName varchar(20), 
    StartDatetime datetime, 
    EndDatetime datetime 
) 

INSERT INTO @SampleData 
(
    FName, 
    StartDatetime, 
    EndDatetime 
) 
VALUES 
('Juan', '2017-08-01 1:00', '2017-08-01 8:00') 

;WITH temp AS 
(
    SELECT sd.FName, sd.StartDatetime AS Interval, sd.EndDatetime 
    FROM @SampleData sd 

    UNION ALL 

    SELECT t.FName, dateadd(minute, 15, t.Interval) AS Interval, t.EndDatetime 
    FROM temp t 
    WHERE dateadd(minute, 15, t.Interval) <= t.EndDatetime 
) 
SELECT t.FName, 
     t.Interval 
FROM temp t 
OPTION (MAXRECURSION 0)

演示链接：http://rextester.com/CELP88345

来源

2017-08-04 10:34:58 TriV

这是更好地使用日期表，但你可以如下产生：如下

Select Fname, RowN as Interval from #dates 
cross apply (
    Select top(datediff(hh,startdatetime, enddatetime)*4+1) RowN =dateadd(mi, (row_number() over(order by (Select NULL)) -1)*15 ,startdatetime) 
     from master..spt_values s1, master..spt_values s2) a

输出：


+-------+-------------------------+ 
| Fname |  Interval   | 
+-------+-------------------------+ 
| Juan | 2017-08-01 01:00:00.000 | 
| Juan | 2017-08-01 01:15:00.000 | 
| Juan | 2017-08-01 01:30:00.000 | 
| Juan | 2017-08-01 01:45:00.000 | 
| Juan | 2017-08-01 02:00:00.000 | 
| Juan | 2017-08-01 02:15:00.000 | 
| Juan | 2017-08-01 02:30:00.000 | 
| Juan | 2017-08-01 02:45:00.000 | 
| Juan | 2017-08-01 03:00:00.000 | 
| Juan | 2017-08-01 03:15:00.000 | 
| Juan | 2017-08-01 03:30:00.000 | 
| Juan | 2017-08-01 03:45:00.000 | 
| Juan | 2017-08-01 04:00:00.000 | 
| Juan | 2017-08-01 04:15:00.000 | 
| Juan | 2017-08-01 04:30:00.000 | 
| Juan | 2017-08-01 04:45:00.000 | 
| Juan | 2017-08-01 05:00:00.000 | 
| Juan | 2017-08-01 05:15:00.000 | 
| Juan | 2017-08-01 05:30:00.000 | 
| Juan | 2017-08-01 05:45:00.000 | 
| Juan | 2017-08-01 06:00:00.000 | 
| Juan | 2017-08-01 06:15:00.000 | 
| Juan | 2017-08-01 06:30:00.000 | 
| Juan | 2017-08-01 06:45:00.000 | 
| Juan | 2017-08-01 07:00:00.000 | 
| Juan | 2017-08-01 07:15:00.000 | 
| Juan | 2017-08-01 07:30:00.000 | 
| Juan | 2017-08-01 07:45:00.000 | 
| Juan | 2017-08-01 08:00:00.000 | 
+-------+-------------------------+

来源

2017-08-04 10:35:33

您可以使用递归CTE来实现预期的结果。

演示 - http://sqlfiddle.com/#!6/821a5/11

with cte as 
(
    select Fname,StartDateTime 
    from Table1 
    union all 
    select Fname,DATEADD(mi,15,StartDateTime) as StartDateTime 
    from cte 
    where DATEADD(mi,15,StartDateTime) <= '2017-01-08 08:00:00:000' 
) 

select Fname, StartDateTime from cte;

来源

2017-08-04 10:43:55

SQL Server的时间间隔，以多行

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