与支架PHP语法错误，当所有支架都关闭

我一直歌厅这个错误：Parse error: syntax error, unexpected '}' in /Users/skline/Sites/tiptap/Site/tiptap/survey_current.php on line 67与支架PHP语法错误，当所有支架都关闭

然而，我的所有支架都关闭！我真的很困惑，在此先感谢..

<?php 

    $dbc = mysql_connect(DATABASE_HOSTNAME,DATABASE_USERNAME, DATABASE_PASSWORD); 
    if(!$dbc){ 
     die('Not connected' .mysql_error()); 
    } 
    // Select database 
    $db_selected = mysql_select_db(DATABASE_DATABASENAME, $dbc); 
    // If fails, exit and cry 
    if (!$db_selected) 
    { 
     die ("can't connect : " .mysql_error()); 
    } 

    function getCurrentSurvey($consumer_id){ 
     $last_survey_sql="SELECT DISTINCT ssr.SET_ID AS SET_ID, 
         ssr.SURVEY_ID AS SURVEY_ID 
         FROM branching_survey_responses AS bsr 
         JOIN survey_set_relation AS ssr 
         ON bsr.SET_ID=ssr.SET_ID 
         AND bsr.SET_ID=(SELECT Max(set_id) 
            FROM branching_survey_responses 
            WHERE CUSTOMER_ID=$consumer_id) 
         AND bsr.CUSTOMER_ID=$consumer_id;"; 

     $last_survey_result=mysql_query($last_survey_sql); 

     $last_set= mysql_result($last_survey_result,0,"SET_ID"); 

     $last_survey= mysql_result($last_survey_result,1,"SURVEY_ID"); 

     $last_question_sql="SELECT DISTINCT QUESTION_ID 
         FROM branching_survey_responses 
         WHERE QUESTION_ID=(SELECT Max(QUESTION_ID) 
              FROM branching_survey_responses 
              WHERE CUSTOMER_ID=$consumer_id 
              AND SET_ID=$last_set) 
         AND CUSTOMER_ID=$consumer_id 
         AND SET_ID=$last_set;"; 

     $last_question_result=mysql_query($last_question_sql); 

     $last_question=mysql_result($last_question_result, 0, "QUESTION_ID"); 

     $survey_count_sql= "SELECT COUNT(*) AS survey_count 
         FROM surveytable;"; 

     $survey_count_result=mysql_query($survey_count_sql); 

     $survey_count=mysql_result($suvery_count_result, 0, "survey_count"); 

     $question_count_sql="SELECT Max(q.QUESTION_ID) AS question_count 
         FROM questions as q 
         JOIN branching_table as bt 
         ON bt.question_id=q.question_id 
         JOIN survey_set_relation as ssr 
         ON ssr.SET_ID=bt.SET_ID 
         AND ssr.SURVEY_ID=$last_survey;"; 

     $question_count_result=mysql_query($question_count_sql); 

     $question_count=mysql_result($question_count_result, 0, "question_count"); 

     $current_survey = array("last_survey"=>$last_survey, "last_question"=>$last_question, "survey_count"=>$survey_count, "last_survey"=>$question_count); 

     return $current_survey 

    } 
    $test=getCurrentSurvey(217); 

    echo $test['last_survey']; 
    echo $test['last_question']; 
    echo $test['survey_count']; 
    echo $test['question_count']; 

    ?>

来源

2011-02-22 Spencer