脚本未正确执行

Question

我有一个创建一个包含从我的相机的当前设置一个文本文件中的shell脚本：

#!/bin/sh 
file="test.txt" 
[[ -f "$file" ]] && rm -f "$file" 

var=$(gphoto2 --summary) 
echo "$var" >> "test.txt" 


if [ $? -eq 0 ] 
then 
    echo "Successfully created file" 
    exit 0 
else 
    echo "Could not create file" >&2 
    exit 1 
fi 

该脚本，因为我认为它应该当我运行它从终端，但是当我运行下面的处理程序是创建的文本文件，但不包含任何来自相机的信息：

import java.util.*; 
import java.io.*; 

void setup() { 
    size(480, 120); 
    camSummary(); 
} 

void draw() { 
} 
void camSummary() { 
    String commandToRun = "./ex2.sh"; 
    File workingDir = new File("/Users/loren/Documents/RC/CamSoft/"); 
    String returnedValues; // value to return any results 


    try { 
     println("in try"); 
     Process p = Runtime.getRuntime().exec(commandToRun, null, workingDir); 
     int i = p.waitFor(); 
     if (i==0) { 
      BufferedReader stdInput = new BufferedReader(new InputStreamReader(p.getInputStream())); 
      while ((returnedValues = stdInput.readLine()) != null) { 
      println(returnedValues); 
      } 
     } else{ 
      println("i is: " + i); 
     } 
    } 
    catch(Throwable t) { 
     println(t); 
    } 
} 

最后，我想直接从剧本到读取一些数据变量，然后在处理中使用这些变量。

有人可以帮我解决这个问题吗？

谢谢

罗兰

备用脚本：

#!/bin/sh 

set -x 
exec 2>&1 

file="test.txt" 
[ -f "$file" ] && rm -f "$file" 


# you want to store the output of gphoto2 in a variable 
# var=$(gphoto2 --summary) 
# problem 1: what if PATH environment variable is wrong (i.e. gphoto2 not accessible)? 
# problem 2: what if gphoto2 outputs to stderr? 
# it's better first to: 

echo first if 
if ! type gphoto2 > /dev/null 2>&1; then 
    echo "gphoto2 not found!" >&2 
    exit 1 
fi 

echo second if 
# Why using var?... 
gphoto2 --summary > "$file" 2>&1 
# if you insert any echo here, you will alter $? 
if [ $? -eq 0 ]; then 
    echo "Successfully created file" 
    exit 0 
else 
    echo "Could not create file" >&2 
    exit 1 
fi 

Answer 1

有你的shell脚本的几个问题。让我们一起纠正并改进。

#!/bin/sh 

file="test.txt" 
[ -f "$file" ] && rm -f "$file" 

# you want to store the output of gphoto2 in a variable 
# var=$(gphoto2 --summary) 
# problem 1: what if PATH environment variable is wrong (i.e. gphoto2 not accessible)? 
# problem 2: what if gphoto2 outputs to stderr? 
# it's better first to: 
if ! type gphoto2 > /dev/null 2>&1; then 
    echo "gphoto2 not found!" >&2 
    exit 1 
fi 
# Why using var?... 
gphoto2 --summary > "$file" 2>&1 
# if you insert any echo here, you will alter $? 
if [ $? -eq 0 ]; then 
    echo "Successfully created file" 
    exit 0 
else 
    echo "Could not create file" >&2 
    exit 1 
fi