打印列表时，Python会以字母开头？

Question

我想我的代码打印为

a. [value1] 
b. [value2] 
c. [value3] 
d. [value4] 
e. [value5] 
f. [value6] 

我现在有一个简单的计数器在

counter = 0 
for key in sorted(word_counter): 
    counter+=1 
    print(counter, key, word_counter[key]) 

Word_counter的形式设立是我已经写了已经完工我只是想另一个函数修复它如何打印。它目前在开始时使用数字，但我希望它使用字母，而不是像第一个例子。

忘了补充一下，一旦它打z我想接下来的字母是aa。 BB。等等如此：

x. [value24] 
y. [value25] 
z. [value26] 
aa. [value27] 
bb. [value28] 
cc. [value29] 

通过字母表的每个迭代添加一封信到结束。

Answer 1

这是非常简单的：

>>> import string 
>>> from itertools import cycle 
>>> x = range(100) 
>>> letters = string.ascii_lowercase 
>>> m = len(letters) 
>>> for i, (let, e) in enumerate(zip(cycle(letters), x)): 
...  print("{}. [{}]".format(let*(i//m+1), e)) 
... 
a. [0] 
b. [1] 
c. [2] 
d. [3] 
e. [4] 
f. [5] 
g. [6] 
h. [7] 
i. [8] 
j. [9] 
k. [10] 
l. [11] 
m. [12] 
n. [13] 
o. [14] 
p. [15] 
q. [16] 
r. [17] 
s. [18] 
t. [19] 
u. [20] 
v. [21] 
w. [22] 
x. [23] 
y. [24] 
z. [25] 
aa. [26] 
bb. [27] 
cc. [28] 
dd. [29] 
ee. [30] 
ff. [31] 
gg. [32] 
hh. [33] 
ii. [34] 
jj. [35] 
kk. [36] 
ll. [37] 
mm. [38] 
nn. [39] 
oo. [40] 
pp. [41] 
qq. [42] 
rr. [43] 
ss. [44] 
tt. [45] 
uu. [46] 
vv. [47] 
ww. [48] 
xx. [49] 
yy. [50] 
zz. [51] 
aaa. [52] 
bbb. [53] 
ccc. [54] 
ddd. [55] 
eee. [56] 
fff. [57] 
ggg. [58] 
hhh. [59] 
iii. [60] 
jjj. [61] 
kkk. [62] 
lll. [63] 
mmm. [64] 
nnn. [65] 
ooo. [66] 
ppp. [67] 
qqq. [68] 
rrr. [69] 
sss. [70] 
ttt. [71] 
uuu. [72] 
vvv. [73] 
www. [74] 
xxx. [75] 
yyy. [76] 
zzz. [77] 
aaaa. [78] 
bbbb. [79] 
cccc. [80] 
dddd. [81] 
eeee. [82] 
ffff. [83] 
gggg. [84] 
hhhh. [85] 
iiii. [86] 
jjjj. [87] 
kkkk. [88] 
llll. [89] 
mmmm. [90] 
nnnn. [91] 
oooo. [92] 
pppp. [93] 
qqqq. [94] 
rrrr. [95] 
ssss. [96] 
tttt. [97] 
uuuu. [98] 
vvvv. [99] 

Answer 2

利用字符串包。

import string

list_of_alphabets = list(string.ascii_lowercase)

for i in range(your number(not greater than 26)): print list_of_alphabets[i] #your task of printing value

Answer 3

import string 

In [7]:  def letter(n): 
    ...:   alphabet = string.ascii_lowercase 
    ...:  
    ...:   count = 0 
    ...:   while count < n: 
    ...:    iteration = (int(count/26.) + 1) 
    ...:    letter = alphabet[count % 26] 
    ...:    yield letter * iteration 
    ...:    count += 1 
    ...:  
    ...:  print '\n'.join(['{0} value{1}'.format(l, i) for i, l in enumerate(letter(100))]) 

a value0 
b value1 
c value2 
d value3 
e value4 
f value5 
g value6 
... 
dd value29 
ee value30 
ff value31 
gg value32 
hh value33 
ii value34 
jj value35 
...