2017-02-26 70 views
0

我想仅通过标识获取用户deleted=0。我试过过滤一个查询,然后通过使用SQLAlchemy标识获得一行

user = User.query.filter_by(deleted=0).get(id) 

但是出错了。如何过滤查询并通过ID获取?

Traceback (most recent call last): 
    File "<stdin>", line 1, in <module> 
    File "/home/david/.virtualenvs/flask-sqlalchemy/lib/python3.6/site-packages/sqlalchemy/orm/query.py", line 831, in get 
    return self._get_impl(ident, loading.load_on_ident) 
    File "/home/david/.virtualenvs/flask-sqlalchemy/lib/python3.6/site-packages/sqlalchemy/orm/query.py", line 864, in _get_impl 
    return fallback_fn(self, key) 
    File "/home/david/.virtualenvs/flask-sqlalchemy/lib/python3.6/site-packages/sqlalchemy/orm/loading.py", line 177, in load_on_ident 
    q._get_condition() 
    File "/home/david/.virtualenvs/flask-sqlalchemy/lib/python3.6/site-packages/sqlalchemy/orm/query.py", line 350, in _get_condition 
    "get", order_by=False, distinct=False) 
    File "/home/david/.virtualenvs/flask-sqlalchemy/lib/python3.6/site-packages/sqlalchemy/orm/query.py", line 368, in _no_criterion_condition 
    self._no_criterion_assertion(meth, order_by, distinct) 
    File "/home/david/.virtualenvs/flask-sqlalchemy/lib/python3.6/site-packages/sqlalchemy/orm/query.py", line 365, in _no_criterion_assertion 
    "Query with existing criterion. " % meth) 
sqlalchemy.exc.InvalidRequestError: Query.get() being called on a Query with existing criterion. 

回答

2

由于错误提示,get仅适用于未筛选查询的情况。如果你想过滤,也可以用id进行过滤,并使用first

user = User.query.filter_by(id=id, deleted=0).first()