提交按钮不会设置

Question

我们无法获取删除“提交”按钮进行设置，否则会起作用，我们无法理解哪部分代码是错误的。

想象有几列，其中从数据库中包含数据的TD的

// While it goes through each row (which is selected from another SQL query above, but I won't bother pasting that) 
while ($row = mysql_fetch_array($result)) { 
// Variable is equal to the Request ID (e.g. 10) 
$numb = $row['ReqID']; 

// Echo's the table td rows with each column name in the database 
echo "<tr>"; 
echo "<td class='req' align='center'>".$row['ReqID']."</td>"; 
echo "<td class='req' align='center'>".$row['ModTitle']."</td>"; 
echo "<td class='req' align='center'>".$row['BuildingID']."</td>"; 
echo "<td class='req' align='center'>".$row['RoomID']."</td>"; 
echo "<td class='req' align='center'>".$row['Priority']."</td>"; 
echo "<td class='req' align='center'>".$row['W1']."</td>"; 
echo "<td class='req' align='center'>".$row['P1']."</td>"; 
// Delete button also in a td row, uses the variable "$numb" to set the button name 
echo "<td class='req' align='center'><input type='submit' name='{$numb}' value='Delete'></td>"; 
echo "</tr>"; 

// If the delete button is pressed, delete the row (this query works, we tested it, but the button just doesn't set so it doesn't activate the SQL command) 
if (isset($_POST[$numb])) { 
$result2 = mysql_query("DELETE FROM Request WHERE ReqID = {$numb} LIMIT 1", $connection); 
} 
} 

Answer 1

使用hidden输入存储值表行：

以上地方......

<form method="post" action="delete.php"> 

稍微低于...

echo "<td class='req' align='center'><input type='submit' name='submit' value='Delete'>"; 
echo '<input name="hello" type="hidden" value="$numb" /></td>'; 
... 
$number = mysql_real_escape_string($_POST["hello"]); 
$result2 = mysql_query("DELETE FROM Request WHERE ReqID = ".$number." LIMIT 1", $connection); 

底部：

</form> 

注：

你的做法是不够安全的。我可以轻松地编辑DOM并为隐藏字段（或按钮的另一个名称）提供另一个值，从而删除数据库中的其他元素。请记住这一点。