你好,我已经用php填充了一个下拉列表。在选择数值的数据库上运行查询
它看起来像这样: -
$con=mysqli_connect("localhost","clinic","myclinic","myclinic");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$query="SELECT DISTINCT doctor FROM schedule";
$result = mysqli_query($con, $query);
echo "<br><br>
<table border='1'><tr>
<td> Doctor's Name </td>
<td> <select name='doctor'>";
while($row = mysqli_fetch_array($result))
{
echo "<option value='" . $row['doctor'] . "'>" . $row['doctor'] ."</option>";
}
echo "</select>";
现在我有更多的一些下拉列表我的网页上。 我想在列表中选择一名医生时运行脚本 例如,在选择医生时,列出日期应该填入医生可用的日期。执行查询
SELECT days from appointments WHERE doctor="One who was selected";
我该如何做到这一点?
感谢
将两个下拉列表关联起来表示您的意思? 这两个值都来自同一个mysql表 – Ajit
好吧,然后只是从第一个下拉列表中传递值并从中获取所需的列值 – rohitr