2017-03-18 178 views
0

我有一些麻烦来完成我的Mysql查询来返回我所需要的。我是MYSQL中如此长的查询的新手。子查询中的GROUP_CONCAT只返回一行

SELECT        
    lang_rel_a_id, 
    lang_rel_b_id, 
    lang_rel_id, 
    tla.text_lang_t AS atext, 
    lald.lang_data_lang_id AS laid, 
    lald.lang_data_position AS lapp, 
    lald.lang_data_font_weight AS lafw, 
    lald.lang_data_font_size AS lafs, 
    lald.lang_data_font_color AS lafc, 
    lald.lang_data_bg_color AS labg, 
    lasdf.funca AS lafunc, 
    lang_ship, 
    lbld.lang_data_lang_id AS lbid, 
    lbld.lang_data_position AS lbpp, 
    lbld.lang_data_font_weight AS lbfw, 
    lbld.lang_data_font_size AS lbfs, 
    lbld.lang_data_font_color AS lbfc, 
    lbld.lang_data_bg_color AS lbbg, 
    tlb.text_lang_t AS btext, 
    lbsdf.funcb AS lbfunc 

    FROM lang_relation 
     LEFT JOIN 
     (SELECT *, GROUP_CONCAT(text_func_t SEPARATOR ', ') AS funca 
     FROM synt_data_func 
      LEFT JOIN text_func ON text_func_id = synt_df_func 
     GROUP BY synt_df_lang_data 
     ) 
     lasdf ON lang_rel_a_id = lasdf.synt_df_lang_data 

     LEFT JOIN lang_data lald ON lald.lang_data_id = lang_rel_a_id 
     LEFT JOIN text_lang tla ON lald.lang_data_lang_id = tla.text_lang_id 

     LEFT JOIN 
      (SELECT *, GROUP_CONCAT(text_func_t SEPARATOR ', ') AS funcb 
      FROM synt_data_func 
      LEFT JOIN text_func ON text_func_id = synt_df_func 
      GROUP BY synt_df_lang_data 
      ) 
      lbsdf ON lang_rel_b_id = lbsdf.synt_df_lang_data 

     LEFT JOIN lang_data lbld ON lbld.lang_data_id = lang_rel_b_id 
     LEFT JOIN text_lang tlb ON lbld.lang_data_lang_id = tlb.text_lang_id 

     WHERE lang_rel_a_id < lang_rel_b_id        
     GROUP BY lang_rel_id 

我在我的lang_relation表中有两种语言的关系。我需要为它们中的每一个查询2个子表,但其中的一个是包含lang_data_id(= lang_rel_a_id或lang_rel_b_id,= synt_df_lang_data)与可能具有多个值的不同语言函数的文本之间关系的关系表。

我不明白为什么在这个子查询中的group_concat只返回一行。如果我只做这个查询,我会得到所有的结果。但是当我把它放到这个更大的查询中时,一切都很好,但是这.. ..不是。

我language_relation表

CREATE TABLE `lang_relation` 
(
`lang_rel_id` int(11) NOT NULL, 
`lang_rel_a_id` int(11) NOT NULL, 
`lang_rel_b_id` int(11) NOT NULL, 
`lang_ship` tinyint(1) NOT NULL 
) ENGINE=InnoDB DEFAULT CHARSET=utf8; 

的加入lang_data

CREATE TABLE `lang_data` (
`lang_data_id` int(11) NOT NULL, 
`lang_data_pic_key` int(11) NOT NULL, 
`lang_data_position` tinyint(1) NOT NULL, 
`lang_data_lang_id` int(11) NOT NULL, 
`lang_data_font_weight` tinyint(2) NOT NULL, 
`lang_data_font_size` tinyint(2) NOT NULL, 
`lang_data_font_color` tinyint(2) NOT NULL, 
`lang_data_bg_color` tinyint(2) NOT NULL 
) ENGINE=InnoDB DEFAULT CHARSET=utf8; 

而且synt_data_func。 text_table是一个带有id +文本的简单2列表。

CREATE TABLE `synt_data_func` (
    `synt_df_id` int(11) NOT NULL, 
    `synt_df_lang_data` int(11) NOT NULL, 
    `synt_df_func` int(11) NOT NULL 
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_bin; 

我尝试了不同的方法。这似乎是我所需要的最接近的一个。我不知道有多少次我改变了GROUP BY子句,我甚至尝试在父SELECT中执行CONCAT_GROUP ..

我甚至想知道这是否可能,因为子查询将用于2个不同的ID。这是问题吗?

感谢您提前提出任何提示。

+0

这将是有益的,如果你能指定的表和查询的输出,你得到的数据,什么数据应该有预期的输出。小提琴将是完美的。 – trincot

回答

0

我终于明白了。也许它会帮助有类似问题的人。我改变了这个查询的方法。

SELECT 
    lrel.lang_rel_pic_key, 
    lrel.lang_rel_id, 
    langdata_a.lascore, 
    lasdf.func_a, 
    langdata_a.latext, 
    lasf.score_astyle, 
    SUM(lasf.score_astyle) + (langdata_a.lascore) AS atotal, 
    lang_ship, 
    langdata_b.lbtext, 
    langdata_b.lbscore, 
    lbsdf.func_b, 
    lbsf.bformat, 
    lbsf.score_bstyle, 
    SUM(lbsf.score_bstyle) + (langdata_b.lbscore) AS btotal 

    FROM lang_relation lrel 

    INNER JOIN 
    (
     SELECT DISTINCT 
      lald.lang_data_id, 
      lafw.field_value AS lafweight, 
      lafs.field_value AS lafsize, 
      lafc.field_value AS laffc, 
      lafbg.field_value AS lafbg, 
      lapos.field_value AS laposa, 
      tla.text_lang_t AS latext, 
      SUM(lafw.field_value) + (lafs.field_value) + (lafc.field_value) + (lafbg.field_value) + (lapos.field_value) AS lascore 
         FROM lang_data lald 
          LEFT JOIN text_lang tla  ON lald.lang_data_lang_id = tla.text_lang_id 
          LEFT JOIN `fields` lafw ON lald.lang_data_font_weight = lafw.field_id 
          LEFT JOIN `fields` lafs ON lald.lang_data_font_size = lafs.field_id 
          LEFT JOIN `fields` lafc ON lald.lang_data_font_color = lafc.field_id 
          LEFT JOIN `fields` lafbg ON lald.lang_data_bg_color = lafbg.field_id 
          LEFT JOIN `fields` lapos ON lald.lang_data_position = lapos.field_id 
     GROUP BY lald.lang_data_id 

    ) 
    langdata_a ON langdata_a.lang_data_id = lrel.lang_rel_a_id 

    LEFT JOIN 
     (SELECT sdf.synt_df_lang_data, GROUP_CONCAT(latf.text_func_t) AS func_a 
       FROM synt_data_func sdf 
       INNER JOIN text_func latf ON latf.text_func_id = sdf.synt_df_func 
       GROUP BY sdf.synt_df_lang_data 
     ) 
    lasdf ON lasdf.synt_df_lang_data = lrel.lang_rel_a_id 

    LEFT JOIN 
     (
       SELECT sfb.synt_format_lang_data, 
          sfb.synt_format_fields_id, 
          GROUP_CONCAT(sfbf.field_text SEPARATOR ', ') AS aformat, 
          SUM(sfbf.field_value) AS score_astyle 
       FROM synt_format sfb 
       INNER JOIN `fields` sfbf ON sfbf.field_id = sfb.synt_format_fields_id 
       GROUP BY sfb.synt_format_lang_data 
     ) 
     lasf ON lasf.synt_format_lang_data = lrel.lang_rel_a_id     


    INNER JOIN 
    (
     SELECT DISTINCT 
      lbld.lang_data_id, 
      lbfw.field_value AS lbfweight, 
      lbfs.field_value AS lbfsize, 
      lbfc.field_value AS lbffc, 
      lbfbg.field_value AS lbfbg, 
      lbpos.field_value AS lbposa, 
      tlb.text_lang_t AS lbtext, 
      SUM(lbfw.field_value) + (lbfs.field_value) + (lbfc.field_value) + (lbfbg.field_value) + (lbpos.field_value) AS lbscore 
         FROM lang_data lbld 
          LEFT JOIN text_lang tlb  ON lbld.lang_data_lang_id = tlb.text_lang_id 
          LEFT JOIN `fields` lbfw ON lbld.lang_data_font_weight = lbfw.field_id 
          LEFT JOIN `fields` lbfs ON lbld.lang_data_font_size = lbfs.field_id 
          LEFT JOIN `fields` lbfc ON lbld.lang_data_font_color = lbfc.field_id 
          LEFT JOIN `fields` lbfbg ON lbld.lang_data_bg_color = lbfbg.field_id 
          LEFT JOIN `fields` lbpos ON lbld.lang_data_position = lbpos.field_id 
      GROUP BY lbld.lang_data_id 

    ) 
    langdata_b ON langdata_b.lang_data_id = lrel.lang_rel_b_id 


    LEFT JOIN 
     (SELECT sdfb.synt_df_lang_data, GROUP_CONCAT(lbtf.text_func_t) AS func_b 
       FROM synt_data_func sdfb 
       INNER JOIN text_func lbtf ON lbtf.text_func_id = sdfb.synt_df_func 
       GROUP BY sdfb.synt_df_lang_data 
     ) 
    lbsdf ON lbsdf.synt_df_lang_data = lrel.lang_rel_b_id 


    LEFT JOIN 
     (
       SELECT sfb.synt_format_lang_data, 
          sfb.synt_format_fields_id, 
          GROUP_CONCAT(sfbf.field_text SEPARATOR ', ') AS bformat, 
          SUM(sfbf.field_value) AS score_bstyle 
       FROM synt_format sfb 
        INNER JOIN `fields` sfbf ON sfbf.field_id = sfb.synt_format_fields_id 
       GROUP BY sfb.synt_format_lang_data 
     ) 
     lbsf ON lbsf.synt_format_lang_data = lrel.lang_rel_b_id 



    GROUP BY lrel.lang_rel_id 

也许有点长,但究竟需要的是什么输出:-)