从json饲料中删除时间

Question

我有一个json饲料与日期和时间在这种格式发布2016-09-26T02:18:40.000Z我想删除时间T02:18:40.000Z显示。

这是代码

var feedUrl = 'var feedUrl = 'http://www.myfeed.com' 

GetFeed(feedUrl , BuildCreative); //get feeds with feed parser url and callback function 


//callback for feedGetter 
function BuildCreative(data){ 
    console.log(data); 
    for(var i = 0; i < 4; i++){ 

     var split_date = 



     document.body.innerHTML += "<div class='feed-content'><a href="+ data[i].link +" target='_blank'><div id='imgHolder'><img src='" + data[i].image.replace('w=98' , 'w=140') + "'></img></div><p>"+ data[i].title +"</p></a><span class='feed-date'>"+ data[i].published + "</span></div>"; 
    } 
} 

//Get feeds function partly based on jquery 
function GetFeed(url , callback){var request = new XMLHttpRequest();request.open('GET', url, true);request.onload = function() {if (request.status >= 200 && request.status < 400) {var data = JSON.parse(request.responseText);callback(data);} else {console.log('error getting feeds');}};request.onerror = function(e) {console.log(e);};request.send();} 

Answer 1

我实现我想用切片你给我用切片的想法

document.body.innerHTML += "<div class='feed-content'><a href="+data[i].link +" target='_blank'><div id='imgHolder'><img src='" + data[i].image.replace('w=98' , 'w=140') + "'></img></div><p>"+ data[i].title +"</p></a><span class='feed-date'>"+ data[i].published.slice('0' , '10') + "</span></div>"; 

Answer 2

如果使用moment.js试试这个

.startOf('day') 

欲了解更多信息，请参阅this post和this documantation page

如果使用纯JS看this post主要思路是获取日期并将秒，小时和其他设置为零：

d.setHours(0, 0, 0, 0); 

Answer 3

您可以从字符串中创建一个Date对象，然后将其输出的格式设置得相当容易。

var date = new Date("2016-09-26T02:18:40.000Z"); 

var dateString = [ 
    date.getUTCFullYear() , 
    ("0" + (date.getUTCMonth()+1)).slice(-2), 
    ("0" + date.getUTCDate()).slice(-2) 
].join("-");