对象数组中：意外的字符串

我在此代码获取上述错误：对象数组中：意外的字符串

var inputs = { 
    $("<input>").attr({"type":"hidden","name":"collegeID"}).val(collegeID), 
    $("<input>").attr({"type":"hidden","name":"collegeID"}).val(collegeID), 
    $("<input>").attr({"type":"hidden","name":"collegeID"}).val(collegeID), 
    $("<input>").attr({"type":"hidden","name":"collegeID"}).val(collegeID), 
    $("<input>").attr({"type":"hidden","name":"collegeID"}).val(collegeID), 
    $("<input>").attr({"type":"hidden","name":"collegeID"}).val(collegeID) 
}

这看起来很有效的给我。我想.append()变量对一个div，我不想创建一堆不同的变量来做到这一点。

来源

2017-09-25 Chud37

对象语法'{键：值}' – Tushar

您使用数组文本方括号（'[]'）。大括号表示期望键值对的对象。 –

对象需要有键和值 –

inputs需要是Array。使用[]代替{}

var collegeID = ""; 
 
var inputs = [ 
 
    $("<input>").attr({ 
 
    "type": "hidden", 
 
    "name": "collegeID" 
 
    }).val(collegeID), 
 
    $("<input>").attr({ 
 
    "type": "hidden", 
 
    "name": "collegeID" 
 
    }).val(collegeID), 
 
    $("<input>").attr({ 
 
    "type": "hidden", 
 
    "name": "collegeID" 
 
    }).val(collegeID), 
 
    $("<input>").attr({ 
 
    "type": "hidden", 
 
    "name": "collegeID" 
 
    }).val(collegeID), 
 
    $("<input>").attr({ 
 
    "type": "hidden", 
 
    "name": "collegeID" 
 
    }).val(collegeID), 
 
    $("<input>").attr({ 
 
    "type": "hidden", 
 
    "name": "collegeID" 
 
    }).val(collegeID) 
 
] 
 

 
console.log(JSON.stringify(inputs));

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

来源

2017-09-25 11:18:15

对象数组中：意外的字符串

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