2010-07-12 83 views
1

在c#使用LINQ XML我将如何提取用于SetSeg的一个给定的前身与C#的LINQ findind基于先前节点

一定值上的数据例​​如seatseg NUM = 10以下Seatassignment LOC =&

<top> 
<SeatSeg> 
        <Num>9</Num> 
    </SeatSeg> 
    <SeatAssignment> 
        <Loc>032A</Loc> 
    </SeatAssignment> 
    <SeatSeg> 
        <Num>10</Num> 
    </SeatSeg> 
    <SeatAssignment> 
        <Loc>033A</Loc> 
    </SeatAssignment> 
</top> 

回答

1

我跑这个,它写出032A。

string xml = "<top><SeatSeg><Num>9</Num></SeatSeg><SeatAssignment><Loc>032A</Loc></SeatAssignment><SeatSeg><Num>10</Num></SeatSeg><SeatAssignment><Loc>033A</Loc></SeatAssignment></top>"; 
int seatNum = 10; 
XDocument xDoc = XDocument.Parse(xml); 

string seatLoc = (from seatSeg in xDoc.Element("top").Elements("SeatSeg") 
        where seatSeg.Element("Num").Value == seatNum.ToString() 
        select seatSeg 
       ).Single().ElementsBeforeSelf().Last().Element("Loc").Value; 

Console.WriteLine(seatLoc); 

然而,看着XML,它似乎是打印出以下033A是你想要的

string xml = "<top><SeatSeg><Num>9</Num></SeatSeg><SeatAssignment><Loc>032A</Loc></SeatAssignment><SeatSeg><Num>10</Num></SeatSeg><SeatAssignment><Loc>033A</Loc></SeatAssignment></top>"; 
int seatNum = 10; 
XDocument xDoc = XDocument.Parse(xml); 

string seatLoc = (from seatSeg in xDoc.Element("top").Elements("SeatSeg") 
        where seatSeg.Element("Num").Value == seatNum.ToString() 
        select seatSeg 
       ).Single().ElementsAfterSelf().First().Element("Loc").Value; 

Console.WriteLine(seatLoc); 

ElementsBeforeSelf()将会把所有前面的兄弟姐妹。 Last()将获得序列的最后一个。

相反,ElementsAfterSelf()将拉动所有后续的兄弟姐妹。 First()将获得序列的第一个。

+0

谢谢Rchem,你是对的第二个例子正是我所需要的! 我是新来的c#和Linq :)我可以问我是否需要扩展它来处理下面的senario如何处理它? 033A 033B 期望返回033A和033B作为Num是10两个。 感谢您的帮助 – 2010-07-13 12:02:52