2011-12-20 77 views
0

我有一个列表存储数据如下类:建议LINQ查询

public class Values 
    { 
     public int ParamId { get; set; } 
     public DateTime TimeStamp { get; set; } 
     public double Value { get; set; } 
    } 

而且我做了以下内容:

IList<Values> val = new List<Values>(); 
//12 december 2011 10 hour 
Values v1 = new Values { ParamId = 100, TimeStamp = new DateTime(2011, 12, 20, 10, 0, 0), Value = 345.0d }; 
Values v2 = new Values { ParamId = 100, TimeStamp = new DateTime(2011, 12, 20, 10, 0, 1), Value = 350.0d }; 
Values v3 = new Values { ParamId = 100, TimeStamp = new DateTime(2011, 12, 20, 10, 0, 2), Value = 355.0d }; 
Values v4 = new Values { ParamId = 100, TimeStamp = new DateTime(2011, 12, 20, 10, 0, 3), Value = 344.0d }; 

Values g1 = new Values { ParamId = 101, TimeStamp = new DateTime(2011, 12, 20, 10, 0, 0), Value = 3000.0d }; 
Values g2 = new Values { ParamId = 101, TimeStamp = new DateTime(2011, 12, 20, 10, 0, 1), Value = 3100.0d }; 
Values g3 = new Values { ParamId = 101, TimeStamp = new DateTime(2011, 12, 20, 10, 0, 2), Value = 3150.0d }; 
Values g4 = new Values { ParamId = 101, TimeStamp = new DateTime(2011, 12, 20, 10, 0, 3), Value = 3125.0d }; 

Values v5 = new Values { ParamId = 100, TimeStamp = new DateTime(2011, 12, 20, 10, 3, 0), Value = 355.0d }; 
Values v6 = new Values { ParamId = 100, TimeStamp = new DateTime(2011, 12, 20, 10, 3, 1), Value = 360.0d }; 
Values v7 = new Values { ParamId = 100, TimeStamp = new DateTime(2011, 12, 20, 10, 3, 2), Value = 365.0d }; 
Values v8 = new Values { ParamId = 100, TimeStamp = new DateTime(2011, 12, 20, 10, 3, 3), Value = 360.0d }; 

Values g5 = new Values { ParamId = 101, TimeStamp = new DateTime(2011, 12, 20, 10, 3, 0), Value = 3150.0d }; 
Values g6 = new Values { ParamId = 101, TimeStamp = new DateTime(2011, 12, 20, 10, 3, 1), Value = 3200.0d }; 
Values g7 = new Values { ParamId = 101, TimeStamp = new DateTime(2011, 12, 20, 10, 3, 2), Value = 3250.0d }; 
Values g8 = new Values { ParamId = 101, TimeStamp = new DateTime(2011, 12, 20, 10, 3, 3), Value = 3225.0d }; 
//............... up to 57 minutes 

Values v9 = new Values { ParamId = 100, TimeStamp = new DateTime(2011, 12, 20, 10, 57, 0), Value = 350.0d }; 
Values v10 = new Values { ParamId = 100, TimeStamp = new DateTime(2011, 12, 20, 10, 57, 1), Value = 365.0d }; 
Values v11 = new Values { ParamId = 100, TimeStamp = new DateTime(2011, 12, 20, 10, 57, 2), Value = 367.0d }; 
Values v12 = new Values { ParamId = 100, TimeStamp = new DateTime(2011, 12, 20, 10, 57, 3), Value = 370.0d }; 

Values g9 = new Values { ParamId = 101, TimeStamp = new DateTime(2011, 12, 20, 10, 57, 0), Value = 3250.0d }; 
Values g10 = new Values { ParamId = 101, TimeStamp = new DateTime(2011, 12, 20, 10, 57, 1), Value = 3240.0d }; 
Values g11 = new Values { ParamId = 101, TimeStamp = new DateTime(2011, 12, 20, 10, 57, 2), Value = 3200.0d }; 
Values g12 = new Values { ParamId = 101, TimeStamp = new DateTime(2011, 12, 20, 10, 57, 3), Value = 3235.0d }; 

val.Add(v1); val.Add(v2); val.Add(v3); val.Add(v4); 
val.Add(v5); val.Add(v6); val.Add(v7); val.Add(v8); 
val.Add(v9); val.Add(v10); val.Add(v11); val.Add(v12); 

val.Add(g1); val.Add(g2); val.Add(g3); val.Add(g4); 
val.Add(g5); val.Add(g6); val.Add(g7); val.Add(g8); 
val.Add(g9); val.Add(g10); val.Add(g11); val.Add(g12); 

我想从这个三小时获取数据计算每个参数的平均值。例如,时间为00:00,00:03,00:06,...,00:57的数据计算00小时参数100和101的平均值。实际上,val列表中的数据范围可能只有几小时或几天。

如何正确执行此操作并使用正确的代码?谢谢。

+0

请你可以写半句多一点清楚?真的很难说出你实际想要达到的目标。 – Michael 2011-12-20 12:47:23

回答

3

事情是这样的:

var valuesByHourQuery = from val in vals 
         group val by val.ParamId into valsByParam 
         select new 
         { 
          ParamId = valsByParam.Key, 
          AvarageValues = from v in valsByParam 
              let timeStampWithoutMinutes = new DateTime(v.TimeStamp.Year, v.TimeStamp.Month, v.TimeStamp.Day, v.TimeStamp.Hour, 0, 0) 
              group v by timeStampWithoutMinutes into valsByHours 
              select new 
              { 
               Hour = valsByHours.Key, 
               Value = valsByHours.Average(v => v.Value) 
              } 
         }; 
+0

对于您的LINQ代码,10小时内的平均值将为357.166666666667,但是正确的值为358.错误在哪里?每小时10小时的值必须包含00:00:00.000和23:59:59.000的范围。谢谢。 – amaranth 2011-12-21 04:50:47