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打开表单操作我有一个表格:如何jQuery的对话框
<form style="display: inline;" action="/player.php" method="post">
<input type="hidden" name="recname" value="'.$row['name'].'">
<input type="hidden" name="recordingdesc" value="'.$row['description'].'">
<input type="hidden" name="reclink" value="$_SESSION['customerid'].'-'.$row['timestamp'].'.wav">
<button type="submit" class="tooltip table-button ui-state-default ui-corner-all" title=" rec"><span class="ui-icon ui-icon-volume-on"></span></button>
</form>
,我想player.php在一个模式对话框打开,并能够显示该发布信息如何才能做到这一点。