排除在POJO响应空字段

Question

我想从一个POJO

**** TransactionHistoryBO POJO的**排除空字段

package main.java.com.as.model; 
 

 
import com.fasterxml.jackson.annotation.JsonInclude; 
 

 
@JsonInclude(JsonInclude.Include.NON_NULL) 
 
public class TransactionHistoryBO 
 
{ 
 
\t private String processId; 
 
\t private String dateTime; 
 
\t private Integer status; 
 
\t private Double pointsEarned; 
 
\t private String productName; 
 
\t private String receiptNumber; 
 
\t 
 
\t public String getProcessId() { 
 
\t \t return processId; 
 
\t } 
 
\t public void setProcessId(String processId) { 
 
\t \t this.processId = processId; 
 
\t } 
 

 

 
\t public String getDateTime() { 
 
\t \t return dateTime; 
 
\t } 
 
\t public void setDateTime(String dateTime) { 
 
\t \t this.dateTime = dateTime; 
 
\t } 
 
\t public Integer getStatus() { 
 
\t \t return status; 
 
\t } 
 
\t public void setStatus(Integer status) { 
 
\t \t this.status = status; 
 
\t } 
 
\t 
 
\t public Double getPointsEarned() { 
 
\t \t return pointsEarned; 
 
\t } 
 

 
\t public void setPointsEarned(Double pointsEarned) { 
 
\t \t this.pointsEarned = pointsEarned; 
 
\t } 
 

 
\t public String getProductName() { 
 
\t \t return productName; 
 
\t } 
 
\t 
 
\t public void setProductName(String productName) { 
 
\t \t this.productName = productName; 
 
\t } 
 
\t 
 
\t public String getReceiptNumber() { 
 
\t \t return receiptNumber; 
 
\t } 
 
\t public void setReceiptNumber(String receiptNumber) { 
 
\t \t this.receiptNumber = receiptNumber; 
 
\t } 
 

 

 

 
}

**

交易历史回复pojo

类型交易记录BO的10

public class TransactionHistoryResponse 
 
{ 
 
\t private ArrayList<TransactionHistoryBO> transactions; 
 
\t 
 
\t @JsonInclude(JsonInclude.Include.NON_NULL) 
 
\t public ArrayList<TransactionHistoryBO> getTransactions() { 
 
\t \t return transactions; 
 
\t } 
 
\t @JsonInclude(Include.NON_NULL) 
 
\t public void setTransactions(ArrayList<TransactionHistoryBO> transactions) { 
 
\t \t this.transactions = transactions; 
 
\t } 
 

 
\t 
 
\t }

数组列表在交易历史响应pojo.This用的是我在response.I我出确切的POJO想排除与空值领域在交易历史BO中。 我试着用@JsonInclude（JsonInclude.Include.NON_NULL）。它不工作.. 也试过用JsonSerialize，但它被弃用.Jackson使用的版本是2.2.2。

任何帮助将appreciated..please帮助..

Answer 1

@JsonInclude(JsonInclude.Include.NON_NULL) 
public class TransactionHistoryBO { ... } 

@JsonInclude(JsonInclude.Include.NON_NULL) 
public class TransactionHistoryResponse { ... } 

public class App { 

    public static void main(String... args) throws JsonProcessingException { 

     ObjectMapper om = new ObjectMapper(); 

     TransactionHistoryResponse thr = new TransactionHistoryResponse(); 
     TransactionHistoryBO thbo = new TransactionHistoryBO(); 
     thbo.setProductName("TEST"); 
     thr.setTransactions(new ArrayList<TransactionHistoryBO>()); 
     thr.getTransactions().add(thbo); 
     System.out.print(om.writerWithDefaultPrettyPrinter().writeValueAsString(thr)); 
    } 

} 

生成输出：

{ 
    "transactions" : [ { 
    "productName" : "TEST" 
    } ] 
} 

没有其他的注释中。只需将@JsonInclude注释添加到类而不是属性。

---

UPDATE：

添加自定义JacksonJsonProvider到您的应用程序

@Provider 
public class CustomJsonProvider extends ResteasyJackson2Provider { 

    @Override 
    public void writeTo(Object value, Class<?> type, Type genericType, Annotation[] annotations, MediaType mediaType, MultivaluedMap<String, Object> httpHeaders, OutputStream entityStream) throws IOException { 

     ObjectMapper mapper = locateMapper(type, mediaType); 
     mapper.setSerializationInclusion(JsonInclude.Include.NON_NULL); 

     super.writeTo(value, type, genericType, annotations, mediaType, httpHeaders, entityStream); 
    } 

} 

注册此提供商在web.xml

<context-param> 
    <param-name>resteasy.providers</param-name> 
    <param-value>com.package.CustomJsonProvider</param-value> 
</context-param> 

测试有和没有这一点，有用。