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我正在尽量减少向Firebase发送的数据请求数量。我有一个拉动下列数据的快照:如何从Firebase快照将变量分配给子节点中的值?
snap (Hole1) {
GreenBackX = "40.196339";
GreenBackY = "-105.07354";
GreenCenterX = "40.196336";
GreenCenterY = "-105.073409";
GreenFrontX = "40.196342";
GreenFrontY = "-105.073283";
Hazard1 = {
CarryX = "40.196839";
CarryY = "-105.07104";
FrontX = "40.196893";
FrontY = "-105.070626";
Name = "R Fwy Bunker";
};
Hazard2 = {
CarryX = "40.196321";
CarryY = "-105.071922";
FrontX = "40.196383";
FrontY = "-105.071573";
Name = "L Fwy Bunker";
};
Hazard3 = {
CarryX = "40.196622";
CarryY = "-105.072935";
FrontX = "40.196662";
FrontY = "-105.072554";
Name = "R Fwy Bunker 2";
};
Hazard4 = {
CarryX = "40.196176";
CarryY = "-105.073545";
FrontX = "40.196225";
FrontY = "-105.073167";
Name = "L Greenside Bunker";
};
HoleH = "258.74";
HoleX = "40.19664";
HoleY = "-105.070484";
}
什么,我的目标是什么是变量赋值,将是Hazard1\Name
。到目前为止,我只在文档中看到了如何获取初始值的工作示例,我喜欢这样做:let holeX = value?["HoleX"] as? Double ?? 0
,但如果您愿意,我似乎无法找到任何让我进入“第二级”的东西。
有一个例子似乎说你可以通过这种方式引用它:let hazard1Name = value?["Hazard1/Name"]
但我无法让它工作。
谢谢@Paulo第二个就是我一直在寻找 – matador0227
@ matador0227 Geat男人,好运气在你一个! PP! –