如何将字符串中的十六进制值转换为数字？

Question

我有一些代码从串口读取一个字符串，解析一些值（在这种情况下，表示高字节和低字节），然后交换它们并合并它们，以便它们按正确的顺序，然后我想将合并后的值转换为十进制值。

我很难试图将十六进制表示形式转换为十六进制的字符串，然后将结果转换为十进制。

的代码是在这里：

private void OutputUpdateCallbackclusterTxtBox(string data) 
{ 
string cluster; 
string attribute; 
string tempvalueHighByte; 
string tempvalueLowByte; 
string tempvalueHighLowByte; //switched around 
int temporarytemp; 



if (data.Contains("T00000000:RX len 9, ep 01, clus 0x0201") == true)//find our marker in thestring 
{ 
    if (data.Contains("clus") == true) 
    { 
     int index = data.IndexOf("clus"); //if we find it find the index in the string it occurs 
     cluster = data.Substring(index + 5, 6); //use this index add 5 and read in 6 characters from the number to get our value 
     attribute = data.Substring(index + 5, 1); 
     cluster_TXT.Text = cluster; // post the value in the test box 
    } 
    if (data.Contains("payload") == true) 
    { 
     int index = data.IndexOf("payload"); //if we find it find the index in the string it occurs 
     tempvalueHighByte = data.Substring(index + 20, 2); //use this index add 20 and read in 2 characters from the number to get our value 
     tempvalueLowByte = data.Substring(index + 23, 2); //use this index add 23 and read in 2 characters from the number to get our value 
     tempvalueHighLowByte = tempvalueLowByte + tempvalueHighByte; 


     ConvertToHex(tempvalueHighLowByte); 

     temporarytemp= int.Parse(tempvalueHighLowByte); 
     temperatureTxt.Text = ((char)temporarytemp).ToString(); // post the value in the text box 
    } 

Answer 1

转换为十六进制和背部在C＃一样简单，例如

string hex = "FFFFFFFF"; 

// From hex... 
long l = Convert.ToInt64(hex, 16); 

// And back to hex... 
string hex2 = l.ToString("X"); 

Answer 2

试试这个：

int value = Convert.ToInt32("0x0201", 16);