我试图使用模型中的$ validate数组显示自定义消息,如'此字段不应为空'或'名称不为空'。我有两个控制器,主要和用户。
主控制器的索引文件具有登录和注册视图。登录和注册功能的动作部分位于user_controller中。如果登录和注册功能有效,它们将被重定向到主控制器的主页,否则它们将保留在索引页面本身中。
我想验证消息显示在索引页面本身。但是这些消息仅在存在用于登录和注册的单独视图文件时出现,即/views/forms/register.ctp和/views/forms/login.ctp存在。
有没有一种方法来显示这些验证消息,而没有这些功能的单独的视图文件?我在下面给出了我的代码。有人请指导我。
模型类:
<?php
class User extends AppModel {
var $name = 'User';
var $components=array('Auth');
var $validate = array(
'name' => array(
'rule' => 'notEmpty',
'message' =>'Name cannot be null.'
),
'password' => array(
'rule' => 'notEmpty'
),
'email_id' => array(
'rule' => 'notEmpty'
)
);
function registerUser($data)
{
if (!empty($data))
{
$this->data['User']['name']=$data['User']['name'];
$this->data['User']['email_id']=$data['User']['email_id'];
$this->data['User']['password']=$data['User']['password'];
$existingUsers= $this->find('all');
foreach($existingUsers as $existingUser):
if($this->data['User']['email_id']==$existingUser['User']['email_id']){
return 0;
}
else{
$this->save($this->data);
$this->data['User']['id']= $this->find('all',array('fields' => array('User.id'),
'order' => 'User.id DESC'
));
$userId=$this->data['User']['id'][0]['User']['id'];
return $userId;
}
endforeach;
}
}
function loginUser($data)
{
$this->data['User']['email_id']=$data['User']['email_id'];
$this->data['User']['password']=$data['User']['password'];
$login=$this->find('all');
foreach($login as $form):
if($this->data['User']['email_id']==$form['User']['email_id'] && $this->data['User']['password']==$form['User']['password'])
{
$this->data['User']['id']= $this->find('all',array('fields' => array('User.id'),
'conditions'=>array('User.email_id'=> $this->data['User']['email_id'],'User.password'=>$this->data['User']['password'])
));
$userId=$this->data['User']['id'][0]['User']['id'];
return $userId;
}
endforeach;
}
}
?>
控制器类:
<?php
class UsersController extends AppController
{
var $name = 'Users';
var $uses=array('Form','User','Attribute','Result');
var $helpers=array('Html','Ajax','Javascript','Form');
function register()
{
$this->Session->write('userId',$this->User->registerUser($this->data));
$this->User->data=$this->data;
if (!$this->User->validates())
{
$this->Session->setFlash('Please enter valid inputs');
$this->redirect('/main');
return;
}
if($this->Session->read('userId')==0){
$this->Session->setFlash('You are already a registerd member.Log in your account');
$this->redirect('/main');
}
else{
$this->Session->setFlash('User account created');
$this->redirect('/main/home');
}
}
function login()
{
//$userId=$this->User->loginUser($this->data);
$this->Session->write('userId',$this->User->loginUser($this->data));
$this->User->data=$this->data;
if (!$this->User->validates())
{
$this->Session->setFlash('Please enter valid inputs');
$this->redirect('/main');
return;
}
if($this->Session->read('userId')>0){
$this->Session->setFlash('Login Successful');
$this->redirect('/main/home');
break;
}
else{
$this->Session->setFlash('Username and password do not match.');
$this->redirect('/main');
}
}
}
?>
视图模板:
<!-- File: /views/main/index.ctp-->
<div id="register">
<h3>Register</h3>
<?php
echo $form->create('User',array('action'=>'register'));
echo $form->input('name');
echo $form->input('email_id');
echo $form->input('password');
echo $form->end('Register');
?>
</div>
<div id="login">
<h3>Login</h3>
<?php
echo $form->create('User',array('action'=>'login'));
echo $form->input('email_id');
echo $form->input('password');
echo $form->end('Login');
?>
</div>
好吧,我将按照您所述的方式进行更改,但我确实希望将特定验证错误显示在登录页面中。 – Angeline 2009-08-10 10:00:21
正如我所说,如果您在同一页上有两次基本相同的表单,则会遇到自动生成错误消息的问题。另外让我重申一下,我认为登录表单是不必要的。话虽如此,如果你分开你的表单,你可以使用这里描述的方法:http://book.cakephp.org/view/410/Validating-Data-from-the-Controller – deceze 2009-08-10 11:52:04