2016-08-03 104 views
0

我有四个页面,当用户登录时会显示,否则会弹出一个窗口,请登录并登录页面打开。当用户输入用户名和密码时,每次只打开第一页。我想打开第3页。请告诉我一个办法打开时,用户登录......就像在登录时打开不同页面

<?php 
$con = mysql_connect("localhost","root",""); 
$db = mysql_select_db('fyp',$con); 

if(isset($_POST['login'])) 
{ 
$user_name = $_SESSION['user_name'] = $_POST['user_name']; 
$user_pass = $_POST['user_pass']; 


$query = "select * from user_login where user_name='".$user_name."' AND user_pass='".$user_pass."'"; 
$run = mysql_query($query); 
if(mysql_num_rows($run)>0){ 

echo "<script>window.open('register_event.php?logged=logged in Successfully..!!!','_self')</script>"; // it is the page 1 
echo "<script>window.open('register_executive.php?logged=logged in Successfully..!!!','_self')</script>"; // it is page 2 
} 
else{ 
    echo "<script>alert('password or user name is incorrect!')</script>"; 
} 
} 

?> 

回答

0

更改_self_blank每一个单独的页面,也就是atarget属性。

阅读this的解释。

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