我在尝试在linux下安装交叉编译器时遇到困难。 我下载了一个似乎没问题的工具链,但接下来呢?我需要在控制台中键入什么命令才能使其安装?如何安装gcc交叉编译器
目的是将C代码转换为MIPS(小端)代码。
其实我需要一次只有2码,所以如果有人只能说明我在MIPS这些代码,我会很乐意......
第一码:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define SIZE 128
int main()
{
char mychar , string [SIZE];
int i;
int count =0 ;
printf ("Please enter your string: \n\n");
fgets (string, SIZE, stdin);
printf ("Please enter char to find: ");
mychar = getchar();
for (i=0 ; string[i] != '\0' ; i++)
if (string[i] == mychar)
count++;
printf ("The char %c appears %d times\n" ,mychar ,count);
return 0;
}
第二码:
#include <stdio.h>
#include <string.h>
void SIFT(int x_arr[ ], int y_arr[]);
int main()
{
int x[20] = {0} , y[20] = {0};
int m=0,temp=0,curr=0,i=0,j=0;
printf("Please enter your numbers now:\n\n");
/*enter numbers one by one. if x[i+1] value < x[i] value, err msg.
when user want to end the series he must enter '0' which means end of string (it wont included in x[]) */
while ((scanf("%d",&temp)) != 5)
{
if (temp >= curr)
{
x[i] = temp;
curr = temp;
i++;
}
else
{
printf("The numbers are not at the right order !\n\nProgram will now terminate...\n\n");
}
}
SIFT(x,y);
for (i=0 ; y[i]=='0' ; i++) /*strlen(y) without ('0')'s includes*/
m++;
/*Prints m , y's organs*/
printf("\n\nm = %d",m);
printf("Y = ");
while (y[j]!='0')
{
printf ("%d ,",y[j]);
j++;
}
return 0;
}
void SIFT(int x_arr[ ], int y_arr[])
{
int i=0,j=0;
while (x_arr[i] != '0')
{
if (x_arr[i] == x_arr[i+1]) /*if current val. equals next val. -> jump dbl at x_arr*/
{
y_arr[j] = x_arr[i];
i+=2;
j++;
}
else
{
y_arr[j]=x_arr[i];
i++;
j++;
}
}
}
你不会将代码转换为mips,但编译它 - 尝试运行'mips-gcc'之类的东西。或尝试列出工具链中存档的文件 – fazo 2011-04-14 21:32:40
都尝试过,没有发现任何东西......也许你有一个,只能编译2个代码给我? – 2011-04-14 21:38:14
你想做什么? – 2011-04-14 21:43:32