我想查看Java代码中HTTP请求产生的响应的“源代码”

Question

我的代码只能返回响应状态消息或状态代码，但我需要我的代码以“查看源代码”格式返回响应，即以XML格式：

import java.io.IOException; 
import java.net.URL; 
import java.net.HttpURLConnection; 

public class API{ 
    public static void main(String args[]) throws IOException 
    { 
     URL url = new URL("http://example.com"); 
     HttpURLConnection http = (HttpURLConnection)url.openConnection(); 
     String statusCode = http.getResponseMessage(); 
     System.out.println(statusCode); 
    } 
} 

Answer 1

你必须得到流，然后阅读它。像这样：

import java.io.IOException; 
import java.net.URL; 
import java.net.HttpURLConnection; 

public class API{ 
    public static void main(String args[]) throws IOException 
    { 
     URL url = new URL("http://example.com"); 

     HttpURLConnection http = (HttpURLConnection)url.openConnection(); 
     String statusCode = http.getResponseMessage(); 
     System.out.println(statusCode); 

      //read the result from the server 
      BufferedReader rd = new BufferedReader(new InputStreamReader(http.getInputStream())); 
      StringBuilder sb = new StringBuilder(); 
      String line = null; 
      while ((line = rd.readLine()) != null) 
      { 
       sb.append(line); 
      } 

      System.out.println(sb.toString()); 
    } 
}