如何使用SPARQL将新实例插入到OWL本体中

Question

我想使用SPARQL INSERT语句将新实例插入到本体中。 样本实例：

<owl:NamedIndividual rdf:about="http://www.test123.com/test123-ontology.owl#cap_123"> 
<rdf:type rdf:resource="http://www.test123.com/test123-ontology.owl#HealthBeauty"/> 
<description>Test test test</description> 
<hasPrice rdf:datatype="http://www.w3.org/2001/XMLSchema#integer">49</hasPrice> 
<id rdf:datatype="http://www.w3.org/2001/XMLSchema#integer">123</id> 
</owl:NamedIndividual> 

应插入具有以下属性的新实例：

id: 456 
hasPrice: 15 
description: "Test2 test2 test2" 

我不知道如何完成查询的INSERT部分：

PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#> 
PREFIX owl: <http://www.test123.com/test123-ontology.owl#> 
PREFIX xsd: <http://www.w3.org/2001/XMLSchema#> 
PREFIX oo: <http://www.w3.org/2002/07/owl#> 
INSERT " 
{ 
//... 
} 

Answer 1

解决方案如下：

PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#> 
PREFIX owl: <http://www.test123.com/test123-ontology.owl#> 
PREFIX xsd: <http://www.w3.org/2001/XMLSchema#> 
PREFIX oo: <http://www.w3.org/2002/07/owl#> 

INSERT 
{ 
    owl:cap_456 rdf:type owl:HealthBeauty . 
    owl:cap_456 owl:id 456 . 
    owl:cap_456 owl:hasPrice 15 . 
    owl:cap_456 owl:description 'Test2 test2 test2' . } 
WHERE 
{ 
    FILTER NOT EXISTS 
    { 
    owl:cap_456 rdf:type owl:HealthBeauty . 
    } 
}